为什么python中的这段代码会出现这个错误？类型错误：“int”类型的对象没有 len() 但我在列表中调用它

问题描述

此代码抛出这些错误：

while len(digits) > 1:
TypeError: object of type 'int' has no len()

但我的可变数字是一个列表，对吗？我想列表推导式中一定有我不明白的地方

def per(n):

    if len(str(n)) == 1:
        return n

    else:
        digits = [int(i) for i in str(n)]

        count = 1
        while len(digits) > 1: # TypeError:object of type 'int' has no len()

            result = 1
            for j in digits:
                result *= j
        
            digits = result
            count += 1

    return count

print(per(716235))

解决方法

def per(n):

    if len(str(n)) == 1:
        return n

    else:
        digits = [int(i) for i in str(n)]

        count = 1
        while len(digits) > 1:

            result = 1
            for j in digits:
                result *= j
        
            digits = result # <-------- Right here you are setting digits
                            # <-------- as result which is an integer
            count += 1

    return count

print(per(716235))