问题描述
我有这张桌子
grid_id | criteria_id | start_value| end_value | provider | property1 | property2 | property3
--------|-------------|------------|-----------|----------|-----------|-----------|-----------
1 | 1 | 3 | NULL | internal | 1 | 1 | 1
2 | 1 | 1 | NULL | internal | 1 | 1 | 1
3 | 2 | 1 | NULL | internal | 1 | 9 | 1
4 | 3 | 1 | 100 | internal | 2 | 5 | 1
5 | 1 | 2 | NULL | external | 1 | 7 | 1
我想要的是创建一个返回这样的数据的选择:
criteria_id | start_value| end_value | provider | property1 | property2 | property3
-------------|------------|-----------|----------|-----------|----------- |-----------
1 | 3,1 | NULL | internal | 1 | 1 | 1
2 | 1 | NULL | internal | 1 | 9 | 1
3 | 1 | 100 | internal | 2 | 5 | 1
1 | 2 | NULL | external | 1 | 7 | 1
在表标准中,我有标准的名称和信息是否是一个范围(例如标准 3 是一个范围,我不需要在 start_value 中为它创建逗号分隔值):>
标准表:
criteria_id | criteria_name| is_range
------------|--------------|---------
1 | crit_1 | 0
2 | crit_2 | 0
3 | crit_3 | 1
SELECT c.criteria_name AS criteria,CASE WHEN c.is_by_range = 0
THEN (IsNull(STUFF((
SELECT ',' + CAST(g.start_value AS VARCHAR)
FROM survey_reallocation_scoring_grid g1
WHERE g.grid_id = g1.grid_id AND g.criteria_id = c.criteria_id
FOR XML PATH('')),1,2,''),''))
ELSE
CAST(g.start_value AS VARCHAR)
END AS start_value,g.end_value,g.provider,g.property1,g.property2,g.property3
FROM [grid] g
INNER JOIN criteria c ON g.criteria_id = c.criteria_id
GROUP BY g.grid_id,c.criteria_name,c.criteria_reallocation_scoring_id,c.is_range,g.property3
ORDER BY g.grid_id
我想为 start_value 创建逗号分隔值,其中除了 start_value (end_value,provider,property1,property2,property3) 之外,多行上有一个具有完全相同属性的条件,并且条件不是一个范围。我不想要第 5 行的值,即使它仍然是标准 1,因为它与第 1 行和第 2 行(在初始表中)的属性不同。我尝试使用 STUFF 和 GROUP BY 和 WITH CTE,但是因为我需要保持初始表中的顺序,所以我无法达到预期的结果。关于这个主题的其他问题比这个案例要容易一些,我的想法已经用完了,希望有人能提供一些提示..谢谢!
PS:我不能使用 STRING_AGG,因为我们的 sql Server 版本低于 2017。 :(
解决方法
以下是您问题的查询答案:
select
criteria_id,STRING_AGG(start_value,',') start_value,end_value,provider,property1,property2,property3
from Tbl
group by criteria_id,property3
order by min(grid_id)
;
结果:
+=============+=============+===========+==========+===========+===========+===========+
| criteria_id | start_value | end_value | provider | property1 | property2 | property3 |
+=============+=============+===========+==========+===========+===========+===========+
| 1 | 3,1 | (null) | internal | 1 | 1 | 1 |
+-------------+-------------+-----------+----------+-----------+-----------+-----------+
| 2 | 1 | (null) | internal | 1 | 9 | 1 |
+-------------+-------------+-----------+----------+-----------+-----------+-----------+
| 3 | 1 | 100 | internal | 2 | 5 | 1 |
+-------------+-------------+-----------+----------+-----------+-----------+-----------+
| 1 | 2 | (null) | external | 1 | 7 | 1 |
+-------------+-------------+-----------+----------+-----------+-----------+-----------+
对于较旧的 MS SQL 服务器,您可以使用下一个解决方案:
select
criteria_id,STUFF((
SELECT ',' + CAST(t.start_value as varchar(10))
FROM Tbl AS t
WHERE
Tbl.criteria_id = t.criteria_id
and (Tbl.end_value = t.end_value or (Tbl.end_value is null and t.end_value is null))
and Tbl.provider = t.provider
and Tbl.property1 = t.property1
and Tbl.property2 = t.property2
and Tbl.property3 = t.property3
FOR XML PATH('')
),1,'') start_value,property3
order by min(grid_id)
;