从中间件错误中的异常中获取方法名称

问题描述

我有这个代码

public class ExceptionMiddleware
    {
        private readonly RequestDelegate _next;
        private readonly ILogger<ExceptionMiddleware> _logger;

        public ExceptionMiddleware(RequestDelegate next,ILogger<ExceptionMiddleware> logger)
        {
            _next = next;
            _logger = logger;
        }

        public async Task InvokeAsync(HttpContext httpContext)
        {
            httpContext.Request.EnableBuffering();
            var body = string.Empty;

            // Leave the body open so the next middleware can read it.
            using (var reader = new StreamReader(
                httpContext.Request.Body,encoding: Encoding.UTF8,detectEncodingFromByteOrderMarks: false,bufferSize: 1024,leaveOpen: true))
            {
                body = await reader.ReadToEndAsync();
                httpContext.Request.Body.Position = 0;
            }

            try
            {
                await _next(httpContext);
            }
            catch (Exception ex)
            {
                await HandleExceptionAsync(httpContext,body,ex);
            }
        }

        private async Task HandleExceptionAsync(HttpContext context,string body,Exception exception)
        {
            LogInfrastructure log = new LogInfrastructure 
            {
                Source = "Test",Module = "Test.Module",Event = exception.TargetSite?.Name,};

            var _serializedLog = JsonConvert.SerializeObject(log);

            if (log.Level == LogLevel.Warning)
                _logger.LogWarning(_serializedLog);
            else
                _logger.LogError(_serializedLog);

            context.Response.ContentType = "application/json";
            context.Response.StatusCode = (int)HttpStatusCode.BadRequest;

            await Task.CompletedTask;
        }

Event 中的属性 LogInfrastructure 应设置为引发异常的方法的名称，例如 Stack Trace 中的方法描述 "StackTrace": " at WebApi.Controllers.TestController.GetAll() in C:\\Microservice\\WebApi\\Controllers\\TestController.cs:line 39\r\n，但 ex.TargetSite.Name 的返回值为 MoveNext。

如何返回 WebApi.Controllers.TestController.GetAll() 而不是 MoveNext？

我也试过了，但返回值与 exception.TargetSite?.Name

相同

private string GetEvent(Exception ex)
        {
            var _event = string.Empty;
            if(!string.IsNullOrEmpty(ex.StackTrace))
            {
                StackTrace trace = new StackTrace(ex,true);
                StackFrame stackFrame = trace.GetFrame(trace.FrameCount - 1);
                _event = stackFrame.getmethod().Name;                
            }
            return _event;
        }

解决方法

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