问题描述
我无法显示地图或使用 esri-leafleft 提供的搜索:这里是 typsescript 文件的代码。
import { Component,OnInit } from '@angular/core';
import { Title,Meta } from '@angular/platform-browser';
import "leaflet/dist/leaflet.css";
import * as L from "leaflet";
import "esri-leaflet-geocoder/dist/esri-leaflet-geocoder.css";
import "esri-leaflet-geocoder/dist/esri-leaflet-geocoder";
import * as esri from "esri-leaflet-geocoder";
/*import * as esri from "esri-leaflet";*/ this one is not working i already installed it.
@Component({
selector: 'app-root',templateUrl: './app.component.html',styleUrls: ['./app.component.css']
})
export class AppComponent implements OnInit{
marker;
title = 'Events Management';
constructor() { }
ngOnInit(){
const apiKey = "I already have the key";
const basemapEnum = "ArcGIS:Navigation";
const map = L.map("map",{
minZoom: 2
}).setView([-33.8688,151.2093],14); // Sydney
L.esri.Vector.vectorBasemapLayer(basemapEnum,{
apiKey: apiKey
}).addTo(map);
const searchControl = esri.Geocoding.geosearch({
position: "topright",placeholder: "Enter an address or place e.g. 1 York St",useMapBounds: false,providers: [esri.Geocoding.arcgisOnlineProvider({
apikey: apiKey,nearby: {
lat: -33.8688,lng: 151.2093
},})]
}).addTo(map);
const results = L.layerGroup().addTo(map);
searchControl.on("results",(data) => {
results.clearLayers();
for (let i = data.results.length - 1; i >= 0; i--) {
const lngLatString = `${Math.round(data.results[i].latlng.lng * 100000)/100000},${Math.round(data.results[i].latlng.lat * 100000)/100000}`;
const marker = L.marker(data.results[i].latlng);
marker.bindPopup(`<b>${lngLatString}</b><p>${data.results[i].properties.LongLabel}</p>`)
results.addLayer(marker);
marker.openPopup();
}
});
}
}
错误类型错误:传单__WEBPACK_IMPORTED_MODULE_2__.esri 未定义 这是我在控制台中得到的错误,我到处找,但一无所获,即使我只用 esri 更改了 L,它也不适用于 Vector 部分
解决方法
我不知道 angular,但您已注释掉导入 esri-leaflet 的位置:
/*import * as esri from "esri-leaflet";*/
您应该从 esri-geocoder 重命名您的导入,以免干扰您的 esri 导入:
import * as esri from "esri-leaflet"
import * as EsriGeocoder from "esri-leaflet-geocoder"
如果没有 esri 导入,则 esri 对象不会导入并附加到 L
,任何对 L.esri
的调用都将不起作用。