问题描述
我需要一个来自 MysqL 数据库的序号。我发现如何像这样在 MysqL 中模拟 row_num:
SET @row=0;
SELECT * FROM (
SELECT (@row:=@row+1) AS no,id,name FROM `attribute` ORDER BY id
) t WHERE name LIKE "%Jo%"
我以以下代码开头:
$this->getEntityManager()->getConnection()->exec("SET @counter = 0");
我尝试过:
$this->result = $this->createqueryBuilder('a')
->select('a')
->where($expr->in('att.ordinal_number',$this->createqueryBuilder('att')->
select('(@counter:=@counter+1) AS ordinal_number')->
from(\App\Entity\Attribute::class,'att')->
orderBy('att.id')->getDQL()))
我尝试过:
$this->result = $this->createqueryBuilder('a')
->select('a')
->addSelect('(SELECT (@counter:=@counter+1) AS oridinal_number,'
.' name FROM App:Entity:Atrribute ORDER BY id)')
以上给我:
有人知道如何用MysqL模拟教义中的row_number吗? 提前致谢。
解决方法
AFAIK 没有直接的方法将这些数据库变量合并到 DQL 或查询构建器中,您需要执行 Native SQL,然后使用 ResultSetMapping
类将查询结果映射到您的实体>
SQL
SELECT *
FROM (
SELECT (@row:=@row+1) AS no,id,name
FROM `attribute`,(SELECT @row:=0) t
ORDER BY id
) t WHERE name LIKE "%Jo%"
结果集映射
$rsm = new ResultSetMapping;
$rsm->addEntityResult('Attribute','a');
$rsm->addFieldResult('a','id','id');
$rsm->addFieldResult('a','name','name');
$rsm->addScalarResult('no','no');
$query = $this->_em->createNativeQuery('SELECT *
FROM (
SELECT (@row:=@row+1) AS no,name
FROM attribute,(SELECT @row:=0) t
ORDER BY id
) t WHERE name LIKE ?',$rsm);
$query->setParameter(1,'%Jo%');
$users = $query->getResult();