问题描述
是否可以直接通过管道输入stargazer,而不是使用更复杂的方式?
示例:
date %>%
filter(x1== "yes",x2 == "no") %>%
select(x5,x6) -> df
cols <- c("x5","x6")
stargazer(
df[,cols],type = "text",summary.stat = c("min","p25","mean","p75","max","median","sd","n")
)
解决方法
是的,您应该能够在 select
中直接通过管道传输 stargazer
的结果。
library(dplyr)
library(stargazer)
mtcars %>%
filter(cyl == 6) %>%
select(wt,disp,cyl) %>%
stargazer(type = "text",summary.stat = c("min","p25","mean","p75","max","median","sd","n"))
=================================================================
Statistic Min Pctl(25) Mean Pctl(75) Max Median St. Dev. N
-----------------------------------------------------------------
wt 2.620 2.822 3.117 3.440 3.460 3.215 0.356 7
disp 145 160 183.314 196.3 258 167.6 41.562 7
cyl 6 6 6.000 6 6 6 0.000 7
-----------------------------------------------------------------
,
我们可以使用
library(dplyr)
library(stargazer)
df %>%
select(all_of(cols)) %>%
stargazer(type = "text","n"))