如何从python上的经度和纬度获取邮政编码?

问题描述

在这个 CSV 文件中有一个纬度和经度坐标的数据框:Longlat

我使用此代码尝试获取邮政编码:

import copy

def get_zipcode(df,geolocator,lat_field,lon_field):
    location = geolocator.reverse((df[lat_field],df[lon_field]))
    return location.raw['address']['postcode']


geolocator = geopy.Nominatim(user_agent='myusername') #My OpenMap username

zipcodes = longlat.apply(get_zipcode,axis=1,geolocator=geolocator,lat_field=longlat['LATITUDE_X'],lon_field=longlat['LONGITUDE_X'])

我收到错误

KeyError
"None of [Float64Index([39.0962320000896,39.1462010000896,39.1347670000896,\n 39.1076250000897,39.0928490000897,39.1648900000896,\n 39.1846440000895,39.0970790000897,39.1491220000896,\n 39.1145560000896,\n ...\n 39.1039560000896,

我该如何解决

解决方法

import geopy
import pandas as pd

longlat = pd.read_csv("longlat.csv",encoding = 'utf-8',sep = '\t')
geolocator = geopy.Nominatim(user_agent="check_1")

def get_zip_code(x):
    location = geolocator.reverse("{},{}".format(x['LATITUDE_X'],x['LONGITUDE_X']))
    return location.raw['address']['postcode']
longlat['zipcode'] = longlat.head().apply(lambda x: get_zip_code(x),axis = 1)
print(longlat.head())
   Unnamed: 0  LATITUDE_X  LONGITUDE_X     zipcode
0      124148   39.096232   -84.653337  45233-4555
1      124209   39.146201   -84.468843       45207
2      125298   39.134767   -84.499079       45267
3      125299   39.107625   -84.496675       45202
4      125390   39.092849   -84.388332       45230

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