execute() 函数在调用时没有被执行

问题描述

我正在尝试为我的键盘制作一个键盘映射，以便不使用 Microsoft 无用 IME keyboard。 所以我用 python 写了这个 pynput 代码。

但它似乎没有执行我的execute()函数

   from pynput.keyboard import Key,Controller
   
   current = set()
   keyboard_typ = Controller()
   
   COMBINATIONS = [
   
       {keyboard.KeyCode(char="q")},{keyboard.KeyCode(char="Q")},{keyboard.KeyCode(char="w")},{keyboard.KeyCode(char="W")},{keyboard.KeyCode(char="e")},{keyboard.KeyCode(char="E")},{keyboard.KeyCode(char="r")},{keyboard.KeyCode(char="R")},{keyboard.KeyCode(char="t")},{keyboard.KeyCode(char="T")},{keyboard.KeyCode(char="y")},{keyboard.KeyCode(char="Y")},{keyboard.KeyCode(char="u")},{keyboard.KeyCode(char="U")},{keyboard.KeyCode(char="i")},{keyboard.KeyCode(char="I")},{keyboard.KeyCode(char="o")},{keyboard.KeyCode(char="O")},{keyboard.KeyCode(char="p")},{keyboard.KeyCode(char="P")},{keyboard.KeyCode(char="a")},{keyboard.KeyCode(char="A")},{keyboard.KeyCode(char="s")},{keyboard.KeyCode(char="S")},{keyboard.KeyCode(char="d")},{keyboard.KeyCode(char="D")},{keyboard.KeyCode(char="f")},{keyboard.KeyCode(char="F")},{keyboard.KeyCode(char="g")},{keyboard.KeyCode(char="G")},{keyboard.KeyCode(char="h")},{keyboard.KeyCode(char="H")},{keyboard.KeyCode(char="j")},{keyboard.KeyCode(char="J")},{keyboard.KeyCode(char="k")},{keyboard.KeyCode(char="K")},{keyboard.KeyCode(char="l")},{keyboard.KeyCode(char="L")},{keyboard.KeyCode(char="z")},{keyboard.KeyCode(char="Z")},{keyboard.KeyCode(char="x")},{keyboard.KeyCode(char="X")},{keyboard.KeyCode(char="c")},{keyboard.KeyCode(char="C")},{keyboard.KeyCode(char="v")},{keyboard.KeyCode(char="V")},{keyboard.KeyCode(char="b")},{keyboard.KeyCode(char="B")},{keyboard.KeyCode(char="n")},{keyboard.KeyCode(char="N")},{keyboard.KeyCode(char="m")},{keyboard.KeyCode(char="M")},]
   
   def on_press(key) :
   
       if any([key in COMBO for COMBO in COMBINATIONS]):
           current.add(key)
           if any(all(k in current for k in COMBO) for COMBO in COMBINATIONS):
               execute()
   
   def execute() :
   
       if current == "q":
           
           print("q")
       
   
   def on_release(key) :
   
       if any([key in COMBO for COMBO in COMBINATIONS]):
           current.remove(key)
   
   with keyboard.Listener(on_press=on_press,on_release=on_release) as listener :
       listener.join() 

解决方法

在考虑 Joaquín 的“set to string”理论后，我将 set 转换为 string 它奏效了。

感谢华金。

def execute(current_key) :
    s = str(current_key)
    for i in s :
        if i == "q" :
            print("q")
            #print("\bㅂ") I tested it with a language and it types the normal text too so I prefer adding\b before the letter/word/sentence

,

execute() 有 current 但你从来没有把这样的变量传递给函数，所以你没有比较。你的函数应该是这样的

   def execute(current) :
   
       if current == "q":
           
           print("q")

,

如果您将 current 传递给函数，它将立即按下所有键并使用循环或 if 条件来检查按下的键中的键。或者如果您只需要按下最后一个键，只需传递 key。

def on_press(key) :

   if any([key in COMBO for COMBO in COMBINATIONS]):
       current.add(key)
       if any(all(k in current for k in COMBO) for COMBO in COMBINATIONS):
           execute(current)

def execute(current_key_set) :
   for key in current_key_set:
      print(key)

或

def on_press(key) :

   if any([key in COMBO for COMBO in COMBINATIONS]):
       current.add(key)
       if any(all(k in current for k in COMBO) for COMBO in COMBINATIONS):
           execute(key)

def execute(current_key) :
   print(current_key)