问题描述
我正在尝试为黑白棋游戏编写 django Web 应用程序。我在将新表格呈现到网站时遇到问题。
views.py
def table(request):
if request.method == "POST":
coord = request.POST.keys()
crd = list(coord)[1]
x = crd.split("_")
r = int(x[0]) - 1
c = int(x[1]) - 1
reversi = reversiGame()
grid = draw_grid(reversi)
ctxt = {"table": grid}
return render(request,'table.html',context=ctxt)
模板
{% extends 'base.html' %}
{% block main_content %}
<div style="text-align: center; width: auto;
height:auto; margin-right:auto; margin-left:200px;">
{% for r in table %}
<div style="float:left">
{% for c in r %}
<form action="" method="post">
{% csrf_token %}
{% if c == 2 %}
<input type="submit" style="background: #000000; width:50px; height:50px;
color:white;"
name="{{forloop.counter}}_{{forloop.parentloop.counter}}" value="2">
{% elif c == 1 %}
<input type="submit" style="background: #ffffff; width:50px; height:50px;"
name="{{forloop.counter}}_{{forloop.parentloop.counter}}" value="1">
{% else %}
<input type='submit' style="background: #c1c1c1; width:50px; height:50px;"
name="{{forloop.counter}}_{{forloop.parentloop.counter}}" value="o">
{% endif %}
</form>
{% endfor %}
</div>
{% endfor %}
</div>
{% endblock %}
urls.py
urlpatterns = [
path('',views.HomeView.as_view(),name="home"),path('signup/',views.SignUpView.as_view(),name='signup'),path('profile/<int:pk>/',views.ProfileView.as_view(),name='profile'),path('table/',views.table,name='table')
]
当我尝试在 request.method 中返回 HttpResponse 时,出现以下错误:The view GameConfiguration.views.table didn't return an HttpResponse object. It returned None instead.
如果我将选项卡移到 return render(request,context=ctxt)
的左侧,则无法识别 ctxt 变量,即新的板(它说它在赋值之前使用),这意味着我没有访问权限到新绘制的表格。
我需要 POST 方法中的行和列,以便翻转棋盘和切换播放器。
我真诚地感谢您的时间!谢谢!
解决方法
您的视图函数仅在 request.method == "POST"
时返回响应。当您在浏览器中访问页面并收到错误 The view ... didn't return an HttpResponse object.
时,那是因为通过浏览器发出的请求具有 request.method == "GET"
。
您可以通过在 if
语句之外添加返回方法来修复您的视图方法:
def table(request):
if request.method == "POST":
# Here is where you capture the POST parameters submitted by the
# user as part of the request.POST[...] dictionary.
...
return render(request,'table.html',context=ctxt)
# When the request.method != "POST",a response still must be returned.
# I'm guessing that this should return an empty board.
reversi = ReversiGame()
grid = draw_grid(reversi)
return render(request,context={"table": grid})