在我的情况下如何忽略 KeyError？ Python

编程问答 2022-05-25

问题描述

在使用具有空白或“NA”值的字典时，我试图忽略我的情况下的 KeyError 或其他类型的错误。

这是我的代码。该错误来自使用“CCIV”等股票时，该股票在雅虎财经中没有员工人数。此外，有时有些公司会将董事会成员的薪酬设为“NA”。


# first attempt at something

import requests
from bs4 import BeautifulSoup
import json
import re
from io import StringIO

url_profile = 'https://finance.yahoo.com/quote/{}/profile?p={}'

stock = input("\n\tStock :\t")

# -------- NLP to stock ticker -------------


# Work in progress


# -------- NLP to stock ticker -------------


response = requests.get(url_profile.format(stock,stock))

soup = BeautifulSoup(response.text,'html.parser')

pattern = re.compile(r'\s--\sData\s--\s')
script_data = soup.find('script',text = pattern).contents[0]

start = script_data.find('context')-2

json_data = json.loads(script_data[start:-12])


if ValueError or KeyError:
    pass

# ---- Ticker

symbol = json_data['context']['dispatcher']['stores']['QuoteSummaryStore']['symbol']


# ---- Employees

employees = str(json_data['context']['dispatcher']['stores']['QuoteSummaryStore']['assetProfile']['fullTimeEmployees']


# ---- Titles
title = []
for i in range(3):

    title.append(json_data['context']['dispatcher']['stores']['QuoteSummaryStore']['assetProfile']['companyOfficers'][i]['title'])

# ---- Names
name = []
for i in range(3):

        name.append(json_data['context']['dispatcher']['stores']['QuoteSummaryStore']['assetProfile']['companyOfficers'][i]['name'])

# ---- Ages

age = []
for i in range(3):

        age.append(str(json_data['context']['dispatcher']['stores']['QuoteSummaryStore']['assetProfile']['companyOfficers'][i]['age']))

# ---- Pay

pay = []
for i in range(3):

        pay.append(json_data['context']['dispatcher']['stores']['QuoteSummaryStore']['assetProfile']['companyOfficers'][i]['totalPay']['longFmt'])


# ---- Formatting (cred. "Anon Coward")

rows = [
    ["Ticker :",symbol],["Employees :",employees],["Title :",title[0],title[1],title[2]],["Name :",name[0],name[1],name[2]],["Ages :",age[0],age[1],age[2]],["Pay :",pay[0],pay[1],pay[2]],]

# Build up a max length of each column
lengths = {}
for row in rows:
    for i in range(len(row)):
        lengths[i] = max(lengths.get(i,0),len(row[i]))

for row in rows:
    # For each cell,padd it by the max length
    output = ""
    for i in range(len(row)):
        if len(output) > 0:
            # Add a space between columns
            output += "    "
        cell = row[i] + " " * lengths[i]
        cell = cell[:lengths[i]]
        output += cell
    print(output+"\n")

我尝试过类似的事情：

employees = 0

if str(json_data['context']['dispatcher']['stores']['QuoteSummaryStore']['assetProfile']['fullTimeEmployees']) != KeyError:
    employees = str(json_data['context']['dispatcher']['stores']['QuoteSummaryStore']['assetProfile']['fullTimeEmployees'])

但我仍然收到错误消息。非常感谢帮助。

解决方法

KeyError 异常是当您尝试访问不在字典中的键时引发的异常

你可以使用 try/except

https://realpython.com/python-keyerror/

,

如果您正在寻找一种更简单的方法来获取这些数据，您可以尝试一个名为 yahooquery 的包。免责声明：我是包的作者。

from yahooquery import Ticker

t = Ticker('CCIV')
t.company_officers

            maxAge                  name  age                    title  yearBorn  exercisedValue  unexercisedValue
symbol row                                                                                                        
CCIV   0         1  Mr. Michael S. Klein   56     Chairman,CEO & Pres      1964               0                 0
       1         1   Mr. Lee Jay Taragin   54  Chief Financial Officer      1966               0                 0
error-handlingkeyerrorlistlistpythonyahoo-finance