问题描述
$sqlInstance1 = Get-DbaInstanceProperty -sqlInstance sql | Select-Object ComputerName,Name,Value | Where-Object Name -In ("FullyQualifiednetName","Edition","PhysicalMemory","Processors","VersionString","Collation","IsClustered","ResourceLastUpdateDateTime")
sql 版企业版(64 位)
sql 物理内存 1571485
sql 处理器 40
sql 版本字符串 11.0.7493.4
sql 排序规则 latin1_General_CI_AS
sql IsClustered True
sql ResourceLastUpdateDateTime 24/12/2019 9:58:55 PM
sql FullQualifiednetName PTHsql13.FMG.local
所以我想从上面分配 $ComputerName = ComputerName
、$Edition = Edition
等,然后我可以用它来更新 sql 表 $ComputerName
解决方法
好的。首先,您需要将结果转换为字典,然后使用该属性字典创建一个新对象。
例如:
$dict = @{ }
(Get-DbaInstanceProperty -SqlInstance localhost | Select-Object ComputerName,Name,Value | Where-Object Name -In ("FullyQualifiedNetName","Edition","PhysicalMemory","Processors","VersionString","Collation","IsClustered","ResourceLastUpdateDateTime")).GetEnumerator() | % { $dict.Add($_.Name,$_.Value) }
New-Object -TypeName PSObject -Property $dict
$result = New-Object -TypeName PSObject -Property $dict
$result.FullyQualifiedNetName
$result.Processors
上面的代码应该打印出 FullyQualifiedNetName
值和 Processors
计数。
点符号在这里是您的朋友。由于您存储的是序列化的实际对象,因此您可以使用 .propertiesname
引用存储值的属性。
[array]SQLInstance1 = Get-DbaInstanceProperty -SqlInstance SQL | Select-Object ComputerName,Value | Where-Object Name -In ("FullyQualifiedNetName","ResourceLastUpdateDateTime")
($SQLInstance1.ComputerName.Count + $SQLInstance1.Name.Count + $SQLInstance1.Value.Count); $i++){
[pscustomobject]@{
ComputerName = $($SQLInstance1.ComputerName[$i])
Name = $($SQLInstance1.Name[$i])
Value = $($SQLInstance1.Value[$i])
}
}