问题描述
编辑: 这篇文章与 Asking the user for input until they give a valid response 不同,因为我没有根据响应的数据类型结束循环。字符串和整数都是有效的。只有当两个条目是不同的 数据类型时,循环才应该返回。
我正在尝试通过 input() 收集两个单词或两个整数。 如果两个值都是整数我想计算 answer1**answer2.
如果两个值都是非整数,我想连接字符串。最后,如果数据类型不匹配,我想把用户送到开头输入两个新值。
这是我的尝试。对于您将要看到的内容,我提前表示歉意。
## collect first value
print("Please type a word or an integer:")
answer1 = input()
## check for blanks
if answer1 == "":
print("Blank space detected. Please retry.")
answer1 = input()
## collect second value
print("Please type another word or integer:")
answer2 = input()
## check for blanks
if answer2 == "":
print("Blank space detected. Please retry.")
answer2 = input()
## define test for integer status
def containsInt(intTest):
try:
int(intTest)
return True
except ValueError:
pass
## check for matching data types and produce final value
if containsInt(answer1) == True:
containsInt(answer2)
if containsInt(answer2) == True:
finalInt = (int(answer1))**(int(answer2))
print("\n")
print(finalInt)
else:
print("Sorry,the data types must match - both words or integers.")
continue
else:
containsInt(answer2)
if containsInt(answer2) !=True:
print("\n")
print(answer1 + answer2)
else:
print("Sorry,the data types must match - both words or integers.")
continue
我试着用“继续”让它回到开始,但它对我很生气。你可能会说我是一个完整的新手,这是我的第一篇文章。请不要对我太狠。 :(
解决方法
continue
仅适用于循环,即 for
和 while
。您试图在循环外使用 continue
,这就是 Python 不喜欢它的原因。
你可以做的一件事是检查数据类型是否匹配,然后根据它做一些事情:
if type(answer1) == type(answer2):
if isinstance(answer1,str):
# do string stuff
elif isinstance(answer1,int) or isinstance(answer1,float):
# do calculations
else:
# types match but are not strings or numbers
else:
# types don't match,react accordingly
默认情况下,Python 将输入视为 string
,因此即使给输入一个数字,它也会是 string
类型。您可以通过多种方式解决此问题,其中之一是您例如尝试将输入转换为数字。在这种情况下,float
比 int
效果更好,否则您将无法很好地处理小数。示例:
answer1 = input()
try:
answer1 = float(answer)
except:
pass
这样做的目的是您尝试将默认字符串输入转换为浮点数,如果这不起作用,则它保持为字符串。
,这应该有效:
while True:
answer1 = input("Please type a word or an integer:")
# check for blanks
while answer1 == "":
answer1 = input("Blank space detected. Please retry.")
try:
answer1 = int(answer1)
except ValueError:
pass
answer2 = input("Please type another word or integer:")
# check for blanks
while answer2 == "":
answer2 = input("Blank space detected. Please retry.")
try:
answer2 = int(answer2)
except ValueError:
pass
if type(answer1) == type(answer2):
if type(answer1) == str:
print(answer1 + answer2)
break
elif type(answer1) == int:
print(answer1**answer2)
break
else:
print(f"Sorry,the data types of '{answer1}' and '{answer2}' do not match.")
continue
请注意,如果您输入像 1.5
这样的数字,它将被视为字符串。
所以输入 1.5
和 a
将导致 1.5a