Python - 从“for循环”中获取单个浮点类型输出并组合成一个列表

问题描述

我当前的输出是在我的下一步中不可迭代的单个浮点数：sum() 和 statistics.mean()。我曾尝试嵌套列表理解，但当它不起作用时，我在嵌套循环中尝试了 next，但我得到了同样的错误 - TypeError: 'float' object is not iterable。并且通过使用 [ss]，列出了每个输出，但不会合并到一个列表中。

感谢任何帮助。如果您需要澄清或有任何疑问，请随时提问。

import pandas as pd
import numpy as np
import math
import statistics

frame=[bdrc,bdmp,bdmv,bdsm]     #These are sources selected and then concated for variable,popPrices.
result=pd.concat(frame)
popPrices=result["Price"]

#Grand Mean
xpop=popPrices.mean()           #The mean

for popsq in popPrices:         #An attempt to have each individual sample treated with the grand mean. - success.
   ss=math.pow(popsq - xpop,2)  
   print(ss)                    #This will print floats individually,but need it in a list.

当前浮点输出：

244107.59945389628
54722.0922075194
6765577.961772737
643320.2371350557
...
...

通缉名单输出：

[244107.59945389628,54722.0922075194,6765577.961772737,643320.2371350557,...,...]

解决方法

使用列表理解

ss=[math.pow(popsq - xpop,2) for popsq in popPrices]

,

import pandas as pd
import numpy as np
import math
import statistics

frame=[bdrc,bdmp,bdmv,bdsm]     #These are sources selected and then concated for variable,popPrices.
result=pd.concat(frame)
popPrices=result["Price"]

#Grand Mean
xpop=popPrices.mean()           #The mean

newList = []

for popsq in popPrices:         #An attempt to have each individual sample treated with the grand mean. - success.
   ss=math.pow(popsq - xpop,2)  
   newList.append(ss)   

,

您需要将这些项目添加到列表中；现在你只是将它们分配给一个变量。试试这个：

resultList = []
for popsq in popPrices:treated with the grand mean. - success.
   resultList.append(math.pow(popsq - xpop,2))
print(resultList)
   

,

您可以创建一个空列表并附加您的结果

result=[]
for popsq in popPrices:          
   ss=math.pow(popsq - xpop,2)  
   result.append(ss)