问题描述
这是我尝试过的文本加密和解密代码:
from Crypto.Cipher import DES
from Crypto import Random
def pad(text):
while len(text) % 8 != 0:
text += " "
return text
def removepad(text):
reverse = text[::-1]
for i in range(len(text)):
if reverse[i] == ' ':
pass
else:
break
text = reverse[i:]
text = text[::-1]
return text
# plaintext = input("Enter Plaintext: ")
# key = input("Enter Key:")
plaintext = 'Encryption and Decryption of DES for OFB mode'
key = 'hellokey'
print("Plaintext: ",plaintext)
print("Key: ",key)
print()
iv = Random.new().read(DES.block_size)
cipher = DES.new(key,DES.MODE_OFB,iv)
plaintext = pad(plaintext)
msg = iv + cipher.encrypt(plaintext)
print("Encrypted Text: ")
print(msg)
print()
decCipher = DES.new(key,msg[:DES.block_size])
msgback = decCipher.decrypt(msg[DES.block_size:])
dmsg = removepad(msgback.decode("utf-8"))
print("Decrypted Text: ")
print(dmsg)
明文:OFB模式下DES的加解密 密钥:hellokey
加密文本: b'\xd5\xc5$\xdc\xac=4*\x91\xfa\x8c\x14\xe7\xbf\xb8\xd6a\x99
解密文本: OFB模式下DES的加解密
解决方法
无论您是否必须使用 DES,DES.new(key,...)
都需要 bytes key
而 cipher.encrypt(plaintext)
需要 bytes {{ 1}} 而不是 plaintext
的,所以使用 bytes 文字 str
或编码为 bytes key = b'hellokey'
。