问题描述
使用 FindWindow 获取单个程序的窗口句柄非常简单 但是对于我的程序,我需要启动一个进程的 4 个实例并获取它们的窗口句柄。
目前我正在使用以下代码来启动应用程序
bool utils::launch_file(const char* exe_path,const char* exe_name,const char* params)
{
SHELLEXECUTEINFO ShExecInfo = { 0 };
ShExecInfo.cbSize = sizeof(SHELLEXECUTEINFO);
ShExecInfo.fMask = SEE_MASK_NOCLOSEPROCESS;
ShExecInfo.hwnd = NULL;
ShExecInfo.lpVerb = _T("open");
ShExecInfo.lpFile = _T(exe_name);
ShExecInfo.lpParameters = params;
ShExecInfo.lpDirectory = exe_path;
ShExecInfo.nShow = SW_SHOW;
ShExecInfo.hInstApp = NULL;
return ShellExecuteExA(&ShExecInfo);
}
我正在考虑做类似的事情
bool utils::launch_file(const char* exe_path,const char* params)
{
SHELLEXECUTEINFO ShExecInfo = { 0 };
ShExecInfo.cbSize = sizeof(SHELLEXECUTEINFO);
ShExecInfo.fMask = SEE_MASK_NOCLOSEPROCESS;
ShExecInfo.hwnd = NULL;
ShExecInfo.lpVerb = _T("open");
ShExecInfo.lpFile = _T(exe_name);
ShExecInfo.lpParameters = params;
ShExecInfo.lpDirectory = exe_path;
ShExecInfo.nShow = SW_SHOW;
ShExecInfo.hInstApp = NULL;
auto res = ShellExecuteExA(&ShExecInfo);
//get hwnd
return res;
}
但是我再次启动的应用程序会启动另一个应用程序...
解决方法
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