问题描述
我有一个带有方法 Animal
的类 foo
,它根据跟随可选参数 inplace
的布尔参数 bar
具有不同的返回类型。我想重载该函数,以便在 inplace
的值已知时返回类型是已知的
这是我的代码:
# main.py
from __future__ import annotations
from typing import Optional,overload,Literal
class Animal:
@overload
def foo(self,bar=...,inplace: Literal[False]=...) -> Animal:
...
@overload
def foo(self,inplace: Literal[True]=...) -> None:
...
def foo(
self,bar=None,inplace: bool = False
) -> Optional[Animal]:
...
reveal_type(Animal().foo(bar='a'))
reveal_type(Animal().foo(inplace=True))
reveal_type(Animal().foo(inplace=False))
$ mypy main.py
main.py:8: error: Overloaded function signatures 1 and 2 overlap with incompatible return types
main.py:21: note: Revealed type is 'main.Animal'
main.py:22: note: Revealed type is 'None'
main.py:23: note: Revealed type is 'main.Animal'
Found 1 error in 1 file (checked 1 source file)
https://mypy-play.net/?mypy=latest&python=3.9&gist=49da369f6343543769eed2060fa61639
如何避免第 8 行的 Overloaded function signatures 1 and 2 overlap with incompatible return types
错误?
解决方法
试试:
@overload
def foo(self,inplace: Literal[False]=...,bar=...) -> Animal:
...
@overload
def foo(self,inplace: Literal[True],bar=...,) -> None:
...
def foo(self,inplace=False,bar=None):
...
我改变了 args 的顺序,否则第二次重载不应该是正确的。
,这似乎有效:
from __future__ import annotations
from typing import Optional,overload,Literal
class Animal:
# using defaults
@overload
def foo(self,inplace: Literal[False]=...) -> Animal: ...
# using inplace = True
# with bar
@overload
def foo(self,bar,inplace: Literal[True]) -> None: ...
# without bar
@overload
def foo(self,*,inplace: Literal[True]) -> None: ...
# with bool
@overload
def foo(self,inplace: bool=...) -> Optional[Animal]: ...
def foo(
self,bar=None,inplace = False
):
...
reveal_type(Animal().foo(bar='a'))
reveal_type(Animal().foo(bar='a',inplace=True))
reveal_type(Animal().foo(bar='a',inplace=False))
reveal_type(Animal().foo(inplace=True))
reveal_type(Animal().foo(inplace=False))
reveal_type(Animal().foo())
inplace: bool
reveal_type(Animal().foo(bar='a',inplace=inplace))
reveal_type(Animal().foo(inplace=inplace))
很多重载,但也许这是不可避免的