问题描述
我有一张这样的桌子:
CREATE TABLE IF NOT EXISTS `logging` (
`id` int(6) unsigned NOT NULL,`status` varchar(150) NOT NULL,`timestamp` DATETIME NOT NULL,PRIMARY KEY (`id`)
) DEFAULT CHARSET=utf8;
INSERT INTO `logging` (`id`,`status`,`timestamp`) VALUES
('1','logout','2021-01-01 05:01:00'),('2','login','2021-01-01 06:02:00'),('3','online','2021-01-01 06:03:00'),('4','away','2021-01-01 06:04:00'),('5','2021-01-01 06:05:00'),('6','2021-01-02 04:00:00'),('7','2021-01-02 04:05:00'),('8','2021-01-02 04:07:00'),('9','2021-01-02 04:55:00');
id | 状态 | 时间戳 |
---|---|---|
1 | 注销 | 2021-01-01 05:01:00 |
2 | 登录 | 2021-01-01 06:02:00 |
3 | 在线 | 2021-01-01 06:03:00 |
4 | 离开 | 2021-01-01 06:04:00 |
5 | 在线 | 2021-01-01 06:05:00 |
6 | 注销 | 2021-01-02 04:00:00 |
7 | 登录 | 2021-01-02 04:05:00 |
8 | 在线 | 2021-01-02 04:07:00 |
9 | 注销 | 2021-01-02 04:55:00 |
日期 | A | B |
---|---|---|
2021-01-01 | 2021-01-01 06:03:00 | 2021-01-02 04:00:00 |
2021-01-02 | ... | ... |
2021-01-03 | ... | ... |
规则是,1 个日志日是从 5:00:00 -(第二天)04:49:49。 'A'是从第一次在线(登录后)开始的时间戳,'B'是从第一次退出(在线后)开始的时间戳。
目前我正在使用此查询来应用日志日规则:
select dt,timestamp from (
select id,left(timestamp,10) dt,timestamp,status
from logging
where TIME(timestamp) >= '05:00:00' and status = 'online'
union all
select id,left((timestamp-interval 1 day),status
from logging
where TIME(timestamp) < '05:00:00' and status = 'online'
) x group by dt;
但是我在应用第二条规则来获取时间戳时遇到问题..
更新: 这是测试数据和表格:https://www.db-fiddle.com/f/tDJL2JHwbtSNEurrLEj11r/0 或http://sqlfiddle.com/#!9/aadb80/2
解决方法
SELECT t1.ts A,t3.ts B
FROM test t1
JOIN test t2 ON t1.ts < t2.ts
JOIN test t3 ON t2.ts < t3.ts
WHERE t1.status = 'login'
AND t2.status = 'online'
AND t3.status = 'logout'
AND NOT EXISTS ( SELECT NULL
FROM test t4
WHERE t1.ts < t4.ts
AND t4.ts < t2.ts
AND t4.status IN ('login','online','logout') )
AND NOT EXISTS ( SELECT NULL
FROM test t5
WHERE t2.ts < t5.ts
AND t5.ts < t3.ts
AND t5.status IN ('login','logout') )
AND DATE(t1.ts - INTERVAL 5 HOUR) = DATE(t3.ts - INTERVAL '04:49:49' HOUR_SECOND);