将 Postgresql 转换为 HiveSql

编程问答 2022-05-23

问题描述

如何将下面提到的 postgresql 查询转换为 Hivesql

SELECT
    COUNT(user_id) Total_profiles,COUNT(user_id) FITLER (WHERE profile_date BETWEEN '2020-01-01' AND '2020-03-31') as Q1_profile,COUNT(user_id) FITLER (WHERE profile_date BETWEEN '2020-04-01' AND '2020-06-30') as Q2_profile,COUNT(user_id) FITLER (WHERE profile_date BETWEEN '2020-07-01' AND '2020-09-30') as Q3_profile,COUNT(user_id) FITLER (WHERE profile_date BETWEEN '2020-010-01' AND '2020-12-31') as Q4_profile
FROM 
    customer_profiles
WHERE 
    profile_date BETWEEN '2020-01-01' AND '2020-12-31'

解决方法

像这样使用 CASE 表达式：

SELECT
    COUNT(user_id) Total_profiles,COUNT(case when profile_date BETWEEN '2020-01-01' AND '2020-03-31' then user_id else null end) as Q1_profile,COUNT(case when profile_date BETWEEN '2020-04-01' AND '2020-06-30' then user_id else null end) as Q2_profile,COUNT(case when profile_date BETWEEN '2020-07-01' AND '2020-09-30' then user_id else null end) as Q3_profile,COUNT(case when profile_date BETWEEN '2020-10-01' AND '2020-12-31' then user_id else null end) as Q4_profile
FROM 
    customer_profiles
WHERE 
    profile_date BETWEEN '2020-01-01' AND '2020-12-31'

同样在 Hive 版本 >= 1.3 中你可以使用 quarter 函数：

SELECT
    COUNT(user_id) Total_profiles,COUNT(case when quarter(profile_date)=1 then user_id else null end) as Q1_profile,COUNT(case when quarter(profile_date)=2 then user_id else null end) as Q2_profile,COUNT(case when quarter(profile_date)=3 then user_id else null end) as Q3_profile,COUNT(case when quarter(profile_date)=4 then user_id else null end) as Q4_profile
FROM 
    customer_profiles
WHERE 
    profile_date BETWEEN '2020-01-01' AND '2020-12-31'
hivehiveqlmysqlpostgresqlsqlsql