问题描述
请指导一下。
输入表（表 1）包含 credit_date、credit_amount、debit_date、debit_amount、loan_date、loan_amount 等列。
输出表（表 2）包含日期、credit_payment、Debit_payment、Loan_payment 等列。
Date ：应该结合所有的 credit_date、debit_date 和 Loan_date 值。
Credit_payment：查找给定 credit_date 的信用金额总和。
Debit_payment：查找给定 debit_date 的借记金额总和。
Loan_payment：求给定loan_date的贷款总额
我尝试了以下查询，但没有奏效。
insert into table2
select
date,debit_payment,credit_payment,Loan_payment
from (
select
sum(credit_amount) over parttion by credit_date as credit_payment,sum(debit_amount) over parttion by debit_date as Debit_payment
sum(loan_amount) over parttion by loan_date as Loan_payment
from table1
union all
select credit_date as date from table1
union all
select debit_date as date from table1
union all
select payment_date as date from table1
) t
-------------------------------------------- ----------------------------
我有另一个场景，credit_Date、debit_date 和loan_date 可以相同。 输出表有以下列
日期：应结合 credit_date、debit_date 和loan_date ( credit_date、debit_date 和loan_date 可以相同也可以不同）
**Credit_payment：**查找给定信用日期、实体、货币、所有者的信用金额总和
Debit_payment：查找给定借记日期、实体、货币、所有者的借记金额总和
Loan_payment：查找给定贷款日期、实体、货币、所有者的贷款金额总和，
实体：来自表 1 的值
货币：表 1 中的值
所有者：表 1 中的值
总计：（credit_payment + debit_payement+loan_payment）的总和
请指导一下。
请找到如下截图。
解决方法
您可能需要在联合所有之前明确指定空列：
insert into table2
select *
from (
select credit_date as date,sum(credit_amount) as credit_payment,null as debit_payment,null as loan_payment
from table1
group by credit_date
union all
select debit_date as date,null as credit_payment,sum(debit_amount) as debit_payment,null as loan_payment
from table1
group by debit_date
union all
select loan_date as date,sum(loan_amount) as loan_payment
from table1
group by loan_date
) t
order by date;