问题描述
我有两个 zip 文件。我想看看所有内容(文件名和 zip 中每个文件的内容)是否相同。
有一个 similar question。但答案不支持 zip 文件。
有人有好主意吗?
解决方法
即使您压缩相同的项目,似乎 zip
也会有不同的哈希值。我们可以把它分成两部分:一是解压,二是解压后比较文件夹。
import os
import filecmp
import zipfile
def are_dir_trees_equal(dir1,dir2):
dirs_cmp = filecmp.dircmp(dir1,dir2)
if len(dirs_cmp.left_only)>0 or len(dirs_cmp.right_only)>0 or \
len(dirs_cmp.funny_files)>0:
return False
(_,mismatch,errors) = filecmp.cmpfiles(
dir1,dir2,dirs_cmp.common_files,shallow=False)
if len(mismatch)>0 or len(errors)>0:
return False
for common_dir in dirs_cmp.common_dirs:
new_dir1 = os.path.join(dir1,common_dir)
new_dir2 = os.path.join(dir2,common_dir)
if not are_dir_trees_equal(new_dir1,new_dir2):
return False
return True
BASE_PATH = '/Users/Documents/'
model1 = os.path.join(BASE_PATH,'test1.zip')
model2 = os.path.join(BASE_PATH,'test2.zip')
with zipfile.ZipFile(model1,"r") as zip_ref:
zip_ref.extractall(BASE_PATH)
with zipfile.ZipFile(model2,"r") as zip_ref:
zip_ref.extractall(BASE_PATH)
folder1 = model1.split('.')[0]
folder2 = model2.split('.')[0]
is_equal = are_dir_trees_equal(folder1,folder2)
print(is_equal)
,
我尝试在 python 中使用 zipfile 内置模块。
from zipfile import ZipFile
def compare(file1,file2):
try:
with ZipFile(file1,'r') as file:
f1 = str([x for x in file.infolist()])
with ZipFile(file2,'r') as file:
f2 = str([x for x in file.infolist()])
return f1 == f2
except FileNotFoundError:
return f"Either file at {file1} or {file2} does not exist"
f = compare(file1='storage/1.zip',file2='storage/2.zip')
print(f)
我不知道这是不是正确的方法(如果不是请纠正我)
,这是我的尝试。确保 ZipFiles 包含相同的项目并且这些项目具有匹配的 CRC32 可能就足够了。 (被比较的两个 ZipFiles 具有相同名称和相同 CRC32 但它们是不同文件的可能性有多大?)如果足够好,请省略比较文件内容的循环。
from zipfile import ZipFile
BUFSIZE = 1024
def are_equivalent(filename1,filename2):
"""Compare two ZipFiles to see if they would expand into the same directory structure
without actually extracting the files.
"""
with ZipFile(filename1,'r') as zip1,ZipFile(filename2,'r') as zip2:
# Index items in the ZipFiles by filename. For duplicate filenames,a later
# item in the ZipFile will overwrite an ealier item; just like a later file
# will overwrite an earlier file with the same name when extracting.
zipinfo1 = {info.filename:info for info in zip1.infolist()}
zipinfo2 = {info.filename:info for info in zip2.infolist()}
# Do some simple checks first
# Do the ZipFiles contain the same the files?
if zipinfo1.keys() != zipinfo2.keys():
return False
# Do the files in the archives have the same CRCs? (This is a 32-bit CRC of the
# uncompressed item. Is that good enough to confirm the files are the same?)
if any(zipinfo1[name].CRC != zipinfo2[name].CRC for name in zipinfo1.keys()):
return False
# Skip/omit this loop if matching names and CRCs is good enough.
# Open the corresponding files and compare them.
for name in zipinfo1.keys():
# 'ZipFile.open()' returns a ZipExtFile instance,which has a 'read()' method
# that accepts a max number of bytes to read. In contrast,'ZipFile.read()' reads
# all the bytes at once.
with zip1.open(zipinfo1[name]) as file1,zip2.open(zipinfo2[name]) as file2:
while True:
buffer1 = file1.read(BUFSIZE)
buffer2 = file2.read(BUFSIZE)
if buffer1 != buffer2:
return False
if not buffer1:
break
return True