问题描述
我有 2 个数据框,第一个是文本数据列(超过 10k 行),第二个是关键字(近 100 个列表)
数据帧 1:
Text
a white house cat plays in garden
cat is a domestic species of small carnivorous mammal
cat is walking in garden behind white house
yellow banana is healthy
数据帧 2:
ID Keywords
1 ['cat','white']
2 ['garden','white','cat']
3 ['domestic','mammal']
我想在数据帧 1 中添加带有 ID 的列,其中最大单词数与数据帧 2 匹配。此外,如果超过 1 或 2 个 ID 之间存在联系,则将两个 ID 连接在一起。在某些情况下,没有任何单词匹配,因此,在这种情况下添加“不匹配”。
输出:
Text ID
a white house cat plays in garden 2
cat is a domestic species of small carnivorous mammal 3
cat is walking in behind white house 1,2
yellow banana is healthy 'No Match'
解决方法
这会起作用。它会创建一个包含每个关键字列表的匹配项数的列表,然后在该列表中查找最大值的 ID
。
import pandas as pd
import ast
df1 = pd.DataFrame(['a white house cat plays in garden','cat is a domestic species of small carnivorous mammal','cat is walking in behind white house','yellow banana is healthy'],columns=['Text'])
df2 = pd.DataFrame([ { "ID": 1,"Keywords": "['cat','white']" },{ "ID": 2,"Keywords": "['garden','white','cat']" },{ "ID": 3,"Keywords": "['domestic','mammal']" } ])
df2['Keywords'] = df2['Keywords'].apply(ast.literal_eval)
def get_ids(text):
matches = [len(set(text.split(" ")) & set(i)) for i in df2['Keywords']]
matches_ids = [df2['ID'][index] for index,val in enumerate(matches) if val == max(matches) if max(matches)>0 ]
return ",".join(str(x) for x in matches_ids) if matches_ids else "No Match"
df1['ID'] = df1['Text'].apply(get_ids)
结果:
文本 | ID | |
---|---|---|
0 | 一只白色的家猫在花园里玩耍 | 2 |
1 | 猫是家养的小型食肉哺乳动物 | 3 |
2 | 猫在白宫后面走 | 1,2 |
3 | 黄香蕉很健康 | 无匹配 |