派生列的 Hive (hql) 并找到总数

问题描述

请指导一下

我有一个场景，其中credit_Date、debit_date 和loan_date 可以具有不同的日期值或相同的值。输出表有以下列

日期：应该结合credit_date、debit_date和loan_date（credit_date、debit_date和loan_date可以相同（或）有不同的日期）

Credit_payment：查找给定信用日期、实体、货币、所有者的信用金额总和

Debit_payment：查找给定借记日期、实体、货币、所有者的借记金额总和

Loan_payment：查找给定贷款日期、实体、货币、所有者的贷款金额总和，

实体：来自表 1 的值

货币：表 1 中的值

所有者：表 1 中的值

总计：（credit_payment + debit_payement+loan_payment）的总和

请找到以下屏幕截图。

解决方法

您可以使用与我的 previous answer 中类似的查询，并更改 table1 的格式以方便按日期分组：

select coalesce(credit_date,debit_date,loan_date) as date,coalesce(sum(credit_amount),0) as credit_payment,coalesce(sum(debit_amount),0) as debit_payment,coalesce(sum(loan_amount),0) as loan_payment,entity,currency,owner,0) + coalesce(sum(debit_amount),0) + coalesce(sum(loan_amount),0) as Total
from (
    select credit_date,credit_amount,null as debit_date,null as debit_amount,null as loan_date,null as loan_amount,owner
    from table1
    union all
    select null as credit_date,null as credit_amount,debit_amount,loan_date,loan_amount,owner
    from table1
) t
group by coalesce(credit_date,loan_date),owner