问题描述
我一直在查看其他帖子以了解如何在 c# 中启动应用程序。我正在制作一个应用程序启动器,并添加了过程控制。我写了这段代码:
Process.FileName = "myapp.exe";
Process.Start();
我认为这不是确切的代码,但第 1 行是我遇到错误的地方。错误是即使文件在同一目录下也找不到。
我的ide是visual studio 2019,我使用.net framework 4.8和.net core 5
解决方法
看来您需要改用 ProcessStartInfo
类:
using (Process myProcess = new Process())
{
myProcess.StartInfo.UseShellExecute = false;
myProcess.StartInfo.FileName = "C:\\HelloWorld.exe";
myProcess.StartInfo.CreateNoWindow = true;
myProcess.Start();
// This code assumes the process you are starting will terminate itself.
// Given that is is started without a window so you cannot terminate it
// on the desktop,it must terminate itself or you can do it programmatically
// from this application using the Kill method.
}