线程 1：EXC_BAD_ACCESS代码=1，地址=0x879bb6700CoreData

问题描述

我正在使用 CoreData 在另一个 ViewController 中用一组数据预填充 TableView（我有 Right Detail 单元格类型）。当我实际转到 TableView 时，它崩溃并给我错误“线程 1：EXC_BAD_ACCESS (code=1,address=0x879bb6700)”。

override func tableView(_ tableView: UITableView,cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "Subcell",for: indexPath)
        
    let mSub = self.mSubs![indexPath.row]
    cell.textLabel?.text = mSub.newWord?.lowercased()
    cell.detailTextLabel?.text = mSub.oldWord?.lowercased()
        
    return cell
}

真正让我感到困惑的是，只有在我预先填充 newWord 数据时才会发生错误。 oldWord 数据永远不会崩溃（即使我将 oldWord 设置为保存用于调试的 newWord 数据，反之亦然）。这是我预填充数据的地方：

let launchedBefore = UserDefaults.standard.bool(forKey: "launchedBefore")
if launchedBefore  {
    print("Not first launch.")
} else {
    print("First launch,setting UserDefault.")
    UserDefaults.standard.set(true,forKey: "launchedBefore")
            
    let ogOldWords = ["equals","plus","minus","subtracted by","negative","times","x","multiplied by","over","divided by"," squared","squared","square root of ","square root ","cube root of "," cubed","cubed"," to the ","to the ","open parentheses","close parentheses","zero","one","two","three","four","five","six","sax","sacks","seven","eight","nine","why","ask","eggs","equal","for","too","to","/","d1"]
            
    let ogNewWords = ["=","+","-","⋅","^2","√","∛","^3","^","( "," )","0","1","2","3","4","5","6","7","8","9","Y","X","=","done"]
            
    for i in 0..<ogOldWords.count {
        let mSubO = MathSubs(context: globalVariables.context)
        mSubO.newWord = ogNewWords[i]
        mSubO.oldWord = ogOldWords[i]
    }

    do {
        try globalVariables.context.save()
    }
    catch {
        print("Could not save data")
    }
}

编辑： 我有时会遇到的另一个错误是“Thread 1:”-[CALayer copyWithZone:]: unrecognized selector sent to instance 0x6000029f72a0""

编辑 2： 在处理应用的另一部分（在原始 ViewController 中）时，我再次遇到 newWord 相同的错误。

do {
    mSubs = try globalVariables.context.fetch(MathSubs.fetchRequest())
    for i in 0..<mSubs!.count {
        mainString = mainString.replacingOccurrences(of: mSubs![i].oldWord ?? "",with: mSubs![i].newWord ?? "",options: .literal,range: mainString.startIndex..<mainString.endindex)
    }
}
catch {
    print("Could not fetch data")
}

应用在 newWord 而不是 oldWord 上崩溃。

解决方法

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