问题描述
我正在尝试执行 SET @row := 0;
SELECT CONCAT(@row := @row + 1,' ',ui.firstname) AS 'FullName',d.survey_at_what_blh,ui.status,ui.nature_of_work,ui.level,ui.course_or_section,date(d.date_opened)
FROM (SELECT disTINCT survey_at_what_blh,date_opened,userid FROM daily_report) d
INNER JOIN userinfo ui ON d.userid = ui.id
WHERE date(d.date_opened) BETWEEN '2021-03-11' AND '2021-03-12'
但不幸的是我收到此错误:
zappa init
如您所见,我的 python 版本是 Traceback (most recent call last):
File "/usr/local/bin/zappa",line 5,in <module>
from zappa.cli import handle
File "/usr/local/lib/python3.9/site-packages/zappa/__init__.py",line 9,in <module>
raise RuntimeError(err_msg)
RuntimeError: This version of Python (3.9) is not supported!
Zappa (and AWS Lambda) support the following versions of Python: ['3.6','3.7','3.8']
。我安装了 3.9
以使其与 pyenv
一起工作,但它仍然无法工作。
有什么建议吗?
解决方法
AWS lambda 目前不支持 python 3.9。 您可以在此处查看支持的运行时列表 https://docs.aws.amazon.com/lambda/latest/dg/lambda-runtimes.html