问题描述
考虑下面的代码。这无法与 mypyc 一起正常运行,因为 Proxy
在运行时没有 __dict__
属性。
所以问题是:
谢谢!
import typing
class Proxy:
def __init__(self) -> None:
self.__dict__['__ops'] = []
def __setattr__(self,name: str,value: typing.Any) -> None:
self.__dict__['__ops'].append(('SetAttr',name,value))
def __getattr__(self,name: str) -> "Proxy":
self.__dict__['__ops'].append(('GetAttr',name))
return self
def __setitem__(self,key: typing.Any,value: typing.Any) -> None:
self.__dict__['__ops'].append(('SetItem',key,value))
def __getitem__(self,key: typing.Any) -> "Proxy":
self.__dict__['__ops'].append(('GetItem',key))
return self
def __call__(self,*args: typing.Any,**kwargs: typing.Any) -> None:
self.__dict__['__ops'].append(('Call',args,kwargs))
p = Proxy()
解决方法
将列表定义为普通成员应该与通过 __dict__
定义它具有相同的效果。我没有关于 mypyc 的具体知识,但这应该适用于任何兼容的 Python 3 实现。
class Proxy:
def __init__(self) -> None:
self.__ops = []
def __setattr__(self,name: str,value: typing.Any) -> None:
self.__ops.append(('SetAttr',name,value))
def __getattr__(self,name: str) -> "Proxy":
self.__ops.append(('GetAttr',name))
return self
def __setitem__(self,key: typing.Any,value: typing.Any) -> None:
self.__ops.append(('SetItem',key,value))
def __getitem__(self,key: typing.Any) -> "Proxy":
self.__ops.append(('GetItem',key))
return self
def __call__(self,*args: typing.Any,**kwargs: typing.Any) -> None:
self.__ops.append(('Call',args,kwargs))