问题描述
在我的 discord bot (python) 上,我试图检测或更确切地说是检查命令中发送的消息:如果有人键入命令 $start,该命令应该在 while 循环中检查 $start 之后发送的消息命令。如果发送的消息是“加入”,则应该将发送消息的用户添加到列表中。我试图通过 on_message() 函数检测和保存变量中的消息,但它似乎不起作用,我认为我的代码没有多大意义,但我不知道如何正确实现它。
import discord
from discord.ext import commands
client = commands.Bot(command_prefix = "$")
@client.event
async def on_ready():
print("started")
sentMsg = ""
users = []
@client.event
async def on_message(msg):
if msg.author == client.user:
return
else:
sentMsg = msg.content
print(sentMsg)
@client.command()
async def start(ctx):
print(sentMsg)
await ctx.send("starting ...")
users.append(ctx.author)
while True:
if sentMsg == "join":
ctx.send("Joined!")
sentMsg = ""
client.run(*token*)
我将 sentMsg 变量放在 VS-Code 的 Watch-section 中,尽管它打印了正确的值,但它总是说“不可用”。同样,当在 on_message() 中将鼠标悬停在它上面时,它会说:“sentMsg”未访问 Pylance。 任何人都可以改进我的代码,或者有人有更好的想法来实现它吗?
感谢任何人的帮助
解决方法
您可以使用 client.wait_for 使机器人检测消息,而不是使用 on_message 事件!
例如:
@client.command()
async def start(ctx):
await ctx.send("starting ...")
try:
message = await client.wait_for('message',timeout=10,check=lambda m: m.author == ctx.author and m.channel == ctx.channel and ctx.content == "join") # You can set the timeout to 'None'
# if you don't want it to timeout (then you can also remove the 'asyncio.TimeoutError' except case
# (remember you have to have at least 1 except after a 'try'))
# if you want the bot to cancel this if the message content is not 'join',# take the last statement from the check and put it here with an if
# what you want to do after "join" message
except asyncio.TimeoutError:
await ctx.send('You failed to respond in time!')
return