问题描述
import itertools
host = ["computer1","computer2"]
variants = [".some.domain.com",".another.domain.com"]
for host in host:
merged_list = "\n".join([host + variants_index for variants_index in variants])
merged_list = merged_list.split()
united = list(itertools.chain(merged_list))
print(united)
但我想要以下输出: ['computer1.some.domain.com','computer1.another.domain.com','computer2.some.domain.com','computer2.another.domain.com']
我现在要说的是:
['computer1.some.domain.com','computer1.another.domain.com']
['computer2.some.domain.com','computer2.another.domain.com']
如何将它们全部合并在一起?
解决方法
使用 itertools 产品
from itertools import product
result = [a+b for a,b in product(host,variants)]
#result: ['computer1.some.domain.com','computer1.another.domain.com','computer2.some.domain.com','computer2.another.domain.com']
,
试试这个,你甚至不需要 itertools
,正如在另一个答案的评论中指出的那样,它甚至更快(比 for 循环或 itertools.product
)
united = [h + v for h in host for v in variants]
,
我认为使用简单的嵌套 for 循环会更简单:
united = []
for host in hosts:
for variant in variants:
united.append(host + variant)
您可以将其折叠为列表理解,但我发现嵌套列表理解通常比它们的价值更麻烦。尽管分析确实表明它们更快,尤其是在大输入时。