问题描述
我的井字游戏 pygame 没有正确执行。我错过了什么？
import sys,pygame
from pygame.locals import *
import random
import time
import re
def setup_board(width=860,height=640):
"""A function for setting up a tic-tac-toe board,note that you have to call this multiple times if you draw over it"""
size = width,height
screen = pygame.display.set_mode(size) #sets up the screen to the size we want
screen.fill('white')
pygame.draw.line(screen,'black',(width/3,0),height),3)
pygame.draw.line(screen,(2*width/3,(0,height/3),(860,2*height/3),3)
return screen,width,height
def get_board_position(x,y):
dw,dl = 860//3,640//3
return x//dw,y//dl,dw,dl
def get_draw_position(x,y):
nx,ny,dl = get_board_position(x,y)
return nx*dw + dw/2,ny*dl + dl/2
def toss_coin():
coin_states = ['heads','tails']
return random.choice(coin_states)
def get_computer_move(board):
for row in range(3):
for col in range(3):
if board[row][col] == '':
return row,col
def get_player_move():
"""Returns the player move as a row and column"""
valid_input = False
while not valid_input:
placement = input("Where would you like to play (enter as row,column e.g. 1,3)")
match = re.search('[1,2,3],[1,3]',placement)
valid_input = match is not None
if valid_input:
row,col = placement.split(',')
row,col = int(row)-1,int(col)-1
return row,col
def check_win(board):
"""Checks to see if there is a winner"""
for row in range(3):
if board[row][0] == board[row][1] == board[row][2] != '':
return True
for column in range(3):
if board[0][column] == board[1][column] == board[2][column] != '':
return True
if board[0][0] == board[1][1] == board[2][2] != '':
return True
elif board[2][0] == board[1][1] == board[0][2] != '':
return True
def print_board(board):
"""This function will print a tic-tac-toe board to the console"""
for index,row in enumerate(board):
print('|'.join(row))
if index < 2:
print('-----')
pygame.init()
font = pygame.font.SysFont('arial',110)
small_font = pygame.font.SysFont('arial',30)
screen,height = setup_board()
clock=pygame.time.Clock()#gets the game clock,we are using this to ensure that we only run at 60fps
rx = font.render("X",False,"black")
quit_text = small_font.render("Quit!","red")
active_game = True
board = [['','',''],['','']]
while active_game:
quit_rect = pygame.draw.rect(screen,'gray',(50,50,60,40),1)
screen.blit(quit_text,quit_rect)
for event in pygame.event.get():
if event.type == pygame.QUIT:
sys.exit()
elif event.type == MOUSEBUTTONUP:
ex,ey = event.pos
if quit_rect[0] <= ex <= quit_rect[0] + quit_rect[2] and quit_rect[1] <= ey <= quit_rect[1] + quit_rect[3]:
sys.exit()
else:
screen.blit(rx,get_draw_position(ex,ey))
if check_win(board):
active_game = False
# replace with drawing winner to the screen
print("You win!")
time.sleep(6)
pygame.display.flip()
clock.tick_busy_loop( 60 )
解决方法
我猜您正在将其从控制台应用程序转换为 GUI 应用程序。您允许点击，但您永远不会将它们输入到您的棋盘阵列中，因此您无法检查是否获胜，并且您永远不会让计算机移动。