选择不同的“难度”时，如何让不同的消息弹出？

问题描述

我想要选择不同的“困难”并选择不同的结果，我按开始。 我不能让它工作。我试图在 youtube 上寻找答案，但没有找到任何有用的东西。

import tkinter as tk
from tkinter import messageBox
import random

root = tk.Tk()

root.title("Simple Game")
canvas1 = tk.Canvas(root,width=300,height=300,bg="black")
canvas1.pack()
canvas1.create_text(150,50,text="Simple Game",font="Times",fill="white")
root.resizable(False,False)

exitbutton = tk.Button(root,text="Exit Game",command=root.destroy,fg="black",activebackground="red").place(x=96,y=250)


def startgame():
    if DifficultyList == "Difficulty":
        messageBox.showinfo("disclaimer","You need to choose a difficulty!")
    elif DifficultyList == "Easy":
        messageBox.showinfo("Info","You are Now playing on Easy mode!")


startbutton = tk.Button(root,text="Start",command=startgame,activeforeground="white",activebackground="green").place(x=96,y=150)

canvas1.create_window(150,150,window=exitbutton)
canvas1.create_window(150,window=startbutton)

DifficultyList = (
    "Difficulty","Easy","Medium","Hard"
)

variable = tk.StringVar(root)
variable.set(DifficultyList[0])

Difficulty = tk.OptionMenu(root,variable,*DifficultyList).place(x=94,y=100)

root.mainloop()

解决方法

这是tkinter基础知识的一部分，您需要使用get()从变量/单选按钮中获取值，并与选项列表中的值（DifficultyList )，所以你的函数应该是：

def startgame():
    if variable.get() == DifficultyList[1]: # Check if 2nd item on list is selected
        messagebox.showinfo("Info","You are now playing on Easy mode!")
    elif variable.get() == DifficultyList[2]:
        messagebox.showinfo("Info","You are now playing on Medium mode!")
    elif variable.get() == DifficultyList[3]:
        messagebox.showinfo("Info","You are now playing on Hard mode!")
    else: # If the selection is anything else other than above mentioned,then
        messagebox.showinfo("Disclaimer","You need to choose a difficulty!")

请注意我如何更改您的 if 并将其移至 else，因为它是从列表中选择的唯一语句，因此它是 else 的一部分。是的，您也可以选择任何其他语句作为 else，但这是唯一一个奇怪的语句，所以我选择了它。

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请注意，虽然命名变量要遵循约定，例如列表通常以所有小写字母命名，但类将命名为 PascalCase 并且函数可能使用 camelCase 命名，但通常使用变量都是小写字母。还要检查：Some common naming conventions are for python