问题描述
use itertools::Itertools;
struct Runner {
h: u8,m: u8,s: u8,}
impl Runner {
fn from(v: (u8,u8,u8)) -> Runner {
Runner {
h: v.0,m: v.1,s: v.2,}
}
}
fn string_to_vec(strg: &str) -> Vec<Runner> {
strg.split(",")
.map(|personal_result| personal_result.split('|'))
.flatten()
.map(|x| x.parse::<u8>().unwrap())
.tuples::<(_,_,_)>()
.collect::<Vec<Runner>>()
}
fn stati(strg: &str) -> String {
let run_vec = string_to_vec(strg);
}
所以我试图将元组收集到我的结构的 Vec 中。不知道该怎么做 https://www.codewars.com/kata/55b3425df71c1201a800009c/train/rust
解决方法
你的 from()
函数不会被魔法调用,即使你实现了 trait From
,你也需要显式调用它:
use itertools::Itertools;
struct Runner {
h: u8,m: u8,s: u8,}
impl From<(u8,u8,u8)> for Runner {
fn from(v: (u8,u8)) -> Runner {
Runner {
h: v.0,m: v.1,s: v.2,}
}
}
fn parse_runner(strg: &str) -> Vec<Runner> {
strg.split(",")
.flat_map(|personal_result| personal_result.split('|'))
.map(|x| x.parse::<u8>().unwrap())
.tuples::<(_,_,_)>()
.map(From::from)
.collect::<Vec<Runner>>()
}