问题描述
我有许多开始和结束时间。我将时间的一部分分配给 15 分钟的 bin (4 / hr)。每个 bin 将包含分配给该 bin 的 0、15 或
到达
出发
times
对于每个到达、离开对，所需的输出是一个 96 个值 0:15 的向量。 我可以看到一种使用 for 循环执行此操作的方法，正在寻找更优雅的解决方案。 有什么想法吗？ 提前致谢。
解决方法
我可以看到一种使用 for 循环执行此操作的方法，正在寻找更优雅的解决方案。有什么想法吗？
通常我们可以使用 apply 函数来代替循环，这你当然知道。例如：
# convert the POSIX times to the minutes of the day
dayminutes = mapply(function (r) (as.numeric(r)/60)%%(60*24),times)
# arrival depart
#[1,] 161 490
#[2,] 323 439
#[3,] 359 616
#[4,] 424 728
#[5,] 490 934
# use "cut" to divide the ranges arrival:(depart-1) into 15 min. intervals over the day
apply(dayminutes,1,function(r) as.vector(summary(cut(r['arrival']:(r['depart']-1),0:(4*24)*15,right=F))))
结果是：
[,1] [,2] [,3] [,4] [,5]
[1,] 0 0 0 0 0
[2,] 0 0 0 0 0
[3,] 0 0 0 0 0
[4,] 0 0 0 0 0
[5,] 0 0 0 0 0
[6,] 0 0 0 0 0
[7,] 0 0 0 0 0
[8,] 0 0 0 0 0
[9,] 0 0 0 0 0
[10,] 0 0 0 0 0
[11,] 4 0 0 0 0
[12,] 15 0 0 0 0
[13,] 15 0 0 0 0
[14,] 15 0 0 0 0
[15,] 15 0 0 0 0
[16,] 15 0 0 0 0
[17,] 15 0 0 0 0
[18,] 15 0 0 0 0
[19,] 15 0 0 0 0
[20,] 15 0 0 0 0
[21,] 15 0 0 0 0
[22,] 15 7 0 0 0
[23,] 15 15 0 0 0
[24,] 15 15 1 0 0
[25,] 15 15 15 0 0
[26,] 15 15 15 0 0
[27,] 15 15 15 0 0
[28,] 15 15 15 0 0
[29,] 15 15 15 11 0
[30,] 15 4 15 15 0
[31,] 15 0 15 15 0
[32,] 15 0 15 15 0
[33,] 10 0 15 15 5
[34,] 0 0 15 15 15
[35,] 0 0 15 15 15
[36,] 0 0 15 15 15
[37,] 0 0 15 15 15
[38,] 0 0 15 15 15
[39,] 0 0 15 15 15
[40,] 0 0 15 15 15
[41,] 0 0 15 15 15
[42,] 0 0 1 15 15
[43,] 0 0 0 15 15
[44,] 0 0 0 15 15
[45,] 0 0 0 15 15
[46,] 0 0 0 15 15
[47,] 0 0 0 15 15
[48,] 0 0 0 15 15
[49,] 0 0 0 8 15
[50,] 0 0 0 0 15
[51,] 0 0 0 0 15
[52,] 0 0 0 0 15
[53,] 0 0 0 0 15
[54,] 0 0 0 0 15
[55,] 0 0 0 0 15
[56,] 0 0 0 0 15
[57,] 0 0 0 0 15
[58,] 0 0 0 0 15
[59,] 0 0 0 0 15
[60,] 0 0 0 0 15
[61,] 0 0 0 0 15
[62,] 0 0 0 0 15
[63,] 0 0 0 0 4
[64,] 0 0 0 0 0
[65,] 0 0 0 0 0
[66,] 0 0 0 0 0
[67,] 0 0 0 0 0
[68,] 0 0 0 0 0
[69,] 0 0 0 0 0
[70,] 0 0 0 0 0
[71,] 0 0 0 0 0
[72,] 0 0 0 0 0
[73,] 0 0 0 0 0
[74,] 0 0 0 0 0
[75,] 0 0 0 0 0
[76,] 0 0 0 0 0
[77,] 0 0 0 0 0
[78,] 0 0 0 0 0
[79,] 0 0 0 0 0
[80,] 0 0 0 0 0
[81,] 0 0 0 0 0
[82,] 0 0 0 0 0
[83,] 0 0 0 0 0
[84,] 0 0 0 0 0
[85,] 0 0 0 0 0
[86,] 0 0 0 0 0
[87,] 0 0 0 0 0
[88,] 0 0 0 0 0
[89,] 0 0 0 0 0
[90,] 0 0 0 0 0
[91,] 0 0 0 0 0
[92,] 0 0 0 0 0
[93,] 0 0 0 0 0
[94,] 0 0 0 0 0
[95,] 0 0 0 0 0
[96,] 0 0 0 0 0