问题描述
我有多个 // position
div,img,span {
&.absolute {
position: absolute;
}
&.top-200 {
top: 100px;
}
&.right-100 {
right: 160px;
}
&.transform {
transform: rotate(-15deg);
}
}
//
// z-index
div,img {
&.z-index-10 {
z-index: 10;
}
}
//backgroundColor
div {
&.bg-index {
background-color: #ecd3e8;
}
&.background-no-repeat {
background-repeat: no-repeat;
}
}
// height
div {
&.height-100vh {
height: 100vh;
}
}
div {
&.frame::after {
position: absolute;
display: block;
content: '';
top: 10px;
left: 10px;
width: 200px;
height: 200px;
Box-shadow: 0 4px 10px rgba(51,51,0.3);
background: rgba(221,221,0.25);
background-blend-mode: hard-light;
z-index: 1;
}
}
文件,我想查看我尝试将所有内容组合在一起的内容:
Xtar.gzY
然后:
cat Xtar*.gzY* > 1.tar.gz` >>> 1.tar.gz file (100 gb)
我收到此错误:
tar xvzf 1.tar.gz
解决方法
怎么样:
printf Xtar*.gzY* | xargs tar -tvzf