问题描述
也许有人知道如何做到这一点?为了更好地理解,我附上了截图。我正在使用 ASP.NET。
我成功收到了请求,但我不知道如何处理它以及如何回复。例如消息“Test123”
命名空间 GoogleAsisstantServer.Controllers
{
[路由("api/[控制器]")]
[ApiController]
public class GoogleController : ControllerBase
{
[HttpGet]
public IActionResult Get()
{
var result = new Result();
result.Value1 = 123;
return Ok(result);
}
[HttpPost]
public async Task<IActionResult> PostWebHook()
{
string body;
using (var reader = new StreamReader(Request.Body))
{
body = await reader.ReadToEndAsync();
}
return Ok("Test123");
}
}
public class Result
{
public int Value1 { get; set; }
public int Value2 { get; set; }
}
}
我应该如何处理这里的请求然后返回一些东西?例如消息“Test123”
这就是我得到的,但我不知道如何处理它然后发回响应。
{"handler":{"name":"abc"},"intent":{"name":"actions.intent.MAIN","params":{},"query":"Mit Google sprechen"},"scene":{"name":"actions.scene.START_CONVERSATION","slotFillingStatus":"UNSPECIFIED","slots":{},"next":{"name":"Start_Frage"}},"session":{"id":"ABwppHHVumDrliLJaLSikS6KnIlN7yYv6Z4XJCOYzEZt8Fr08RH6r0wtM2-E0v40lS2p1YosTDfpSCd5Lw","typeOverrides":[],"languageCode":""},"user":{"locale":"de-DE","accountLinkingStatus":"ACCOUNT_LINKING_STATUS_UNSPECIFIED","verificationStatus":"VERIFIED","packageEntitlements":[],"gaiamint":"","permissions":[],"lastSeenTime":"2021-04-01T10:06:59Z"},"home":{"params":{}},"device":{"capabilities":["SPEECH","RICH_RESPONSE","LONG_FORM_AUdio"]}}
解决方法
请求以 JSON 格式发送给您。您需要将其解析为一个对象,以便您可以使用它。
您需要做的第一件事是定义即将退役的对象。这在 request object format 中有记录。
非常基本的例子。
public class Handler
{
public string name { get; set; }
}
public class Params
{
public string UserId { get; set; }
public int NumVisits { get; set; }
}
public class Intent
{
public string name { get; set; }
public Params @params { get; set; }
public string query { get; set; }
}
public class Slots
{
}
public class Next
{
public string name { get; set; }
}
public class Scene
{
public string name { get; set; }
public string slotFillingStatus { get; set; }
public Slots slots { get; set; }
public Next next { get; set; }
}
public class Session
{
public string id { get; set; }
public Params @params { get; set; }
public List<object> typeOverrides { get; set; }
public string languageCode { get; set; }
}
public class User
{
public string locale { get; set; }
public Params @params { get; set; }
public string accountLinkingStatus { get; set; }
public string verificationStatus { get; set; }
public List<object> packageEntitlements { get; set; }
public string gaiamint { get; set; }
public List<object> permissions { get; set; }
public DateTime lastSeenTime { get; set; }
}
public class Home
{
public Params @params { get; set; }
}
public class Device
{
public List<string> capabilities { get; set; }
}
public class Response
{
public Handler handler { get; set; }
public Intent intent { get; set; }
public Scene scene { get; set; }
public Session session { get; set; }
public User user { get; set; }
public Home home { get; set; }
public Device device { get; set; }
}
一旦你定义了你的对象,你就可以反序列化请求。
var values = JsonSerializer.Deserialize<Response>(body);
由于目前还没有人为操作创建库,因此您需要自己完成此操作。
同样,对于响应,您需要发回使用 response object format 格式化的 JSON。