使用简单的 salesforce 获取循环中每个 salesforce 对象的字段名称

编程问答 2022-05-15

问题描述

我正在使用 simple_salesforce 获取对象的所有字段名称的列表。

我有以下内容

from simple_salesforce import Salesforce

sf = Salesforce(username = username,password = pass....) #Connecting to sf

#I'm using salesforce object api names to get all the fields that belong to that object
Api_names = ["Account","Contact","Campaign"]

desc = {}
for obj in Api_names:
    if obj == "Account":
        desc = sf.Account.describe()
    elif obj == "Contact":
        desc = sf.Contact.describe()
    elif obj == "Campaign":
        desc = sf.Campaign.describe()

    field_names_list_1 = [field['name'] for field in desc['fields']]

    #do something with the list... for Now,I'm just adding break
    break

我想写这样的东西

Api_names = ["Account","Campaign"]
for obj in Api_names:
    desc = sf.obj.describe()

但它将 obj 视为 api 名称。我确实尝试过 soql 方式

query = sf.query("SELECT QualifiedApiName FROM FieldDeFinition WHERE
EntityDeFinition.QualifiedApiName IN ('{0}')".format("Account"))

field_names_list_2 = []
for i in range(0,query['totalSize']):
    field_names_list_2.append(query['records'][i]["QualifiedApiName"])

但是，对于 Account 对象，field_names_list_1 和 field_names_list_2 具有不同的长度。 field_names_list_1 包含所有字段，但 field_names_list_2 缺少一些字段。不知道为什么。

我可以在 sf.obj.describe() 中更改什么，以便将 obj 视为实际变量而不是 salesforce 对象名称？

解决方法

在getattr()中使用simple_salesforce动态获取对象代理：

api_names = ["Account","Contact","Campaign"]
for obj in Api_names:
    desc = getattr(sf,obj).describe()
pythonsalesforcesalesforcesimple-salesforce