如何对多个数字进行编码和加密？

编程问答 2022-05-15

问题描述

我有如下 JSON 数据：

{
    "Body": {
        "AccNum": [
            "000405010255","000405010310","000405009777","000401109537","000401113460","000401116861","001805015288","628801537715","000319000184","000401193586","000405111139","000405501186","000760004994","000805015689","000813001320","001105024982","001801080623","001810042371","001825075268","004214109637","004214109638","010310000278","032501004151","044205008102","105701000275","630010075140"
        ]
    }
}

现在我必须一个一个地获取数字并隐藏数字的前 8 位数字，然后对数字进行编码，然后对数字进行加密。我怎样才能为所有数字做这部分？比如前任。首先，它将获取第一个数字，然后在对数字进行编码后隐藏该数字的前 8 位数字，并在获取第二个数字后加密数字，它将处理相同的数字。对于所有数字，我必须这样处理。

解决方法

使用 json 模块和列表切片。您基本上是将 X 8 次与列表项的其他 4 位数字连接起来

import json
a={
    "Body": {
        "AccNum": [
            "000405010255","000405010310","000405009777","000401109537","000401113460","000401116861","001805015288","628801537715","000319000184","000401193586","000405111139","000405501186","000760004994","000805015689","000813001320","001105024982","001801080623","001810042371","001825075268","004214109637","004214109638","010310000278","032501004151","044205008102","105701000275","630010075140"
        ]
    }
}
a["Body"]["AccNum"]=["X"*8 + x[8:] for x in a["Body"]["AccNum"]]
print(json.dumps(a))
encodeencodeencryptionjsonpython