问题描述
如果单词出现在列表中，我正在尝试计算字符串中的所有单词。但是，我的代码仅适用于 unigrams 而不适用于 bigrams 或 trigrams。我如何计算所有三个？
text_df = [['take time'],['spend extra time adjust schedule'],['work more hour extend hour']]
text_df = pd.DataFrame(text_df,columns = ['answer1'])
time_words = ['time','extra time','adjust schedule','extend']
##I tried this but it only counts unigrams
text_df['time_wordcount'] = text_df['answer1'].apply(lambda x: len([wrd for wrd in x.split() if wrd in time_words]))
##Update: This works but it is really long hand
text_df['split'] = text_df['answer1'].apply(lambda x: x.split())
text_df['split2'] = text_df['split'].apply(lambda x: [' '.join(pair) for pair in zip(x,x[1:])])
text_df['split3'] = text_df['split'] + text_df['split2']
text_df['time_wordcount'] = text_df['split3'].apply(lambda x: len([wrd for wrd in x if wrd in time_words]))
有什么想法吗？
解决方法
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