问题描述
我将 graphql nodejs 与 apollo-server 一起使用。 当我尝试时出现此错误:
我已经在解析器中返回了 pubsub.asyncIterator。 它返回错误。另一个项目相同的设置有效,但它不起作用。我在这里检查了一些堆栈问题,但我无法解决。
服务器: App.js
const express = require('express');
const mongoose = require('mongoose');
const { ApolloServer } = require('apollo-server');
const { mainSchema } = require('./graphql/schemas/index');
const { rootResolver } = require('./graphql/resolvers/index');
const app = express();
const server = new ApolloServer({
typeDefs: mainSchema,resolvers: rootResolver,subscriptions: {
path: `/graphql`,onConnect: (connectionParams,webSocket,context) => {
console.log('Client connected');
},onDisconnect: (webSocket,context) => {
console.log('Client disconnected')
},},});
server.listen(3000,"192.168.1.106").then(({ url }) => {
console.log(`? Server ready at ${url}`);
});
订阅解析器
Subscription :{
userNotifications : withFilter(
()=>pubSub.asyncIterator(NEW_NOTIFICATION_CREATE),(payload,variables)=>{
console.log("payload=>",payload);
console.log("variables=>",variables);
return true
}
)}}
PubSub.js
const { PubSub } = require('graphql-subscriptions')
const pubSub =new PubSub()
exports.pubSub = pubSub;
解决方法
我必须使用 subccribe 关键字来定义 subs。谢谢我。 订阅:{ 用户通知:withFilter( 订阅:()=>pubSub.asyncIterator(NEW_NOTIFICATION_CREATE),(有效载荷,变量)=>{ console.log("payload=>",payload); console.log("变量=>",变量); 返回真 } )}}