Java 2 ArrayLists 具有相同顺序的相同元素在相等检查

问题描述

我有一个测试用例来检查对象列表的排序方法，我在排序后打印了两个列表的内容，并且它们具有相同顺序的相同元素。但是 testList.equals(correctList) 返回 false。有谁知道为什么？

测试用例

List<KthPopularNamesReport.KthPopularNames> correctList = new ArrayList<KthPopularNamesReport.KthPopularNames>();
        List<KthPopularNamesReport.KthPopularNames> testList = new ArrayList<KthPopularNamesReport.KthPopularNames>();
        correctList.add(new KthPopularNamesReport.KthPopularNames("A",5,1000,"A"));
        correctList.add(new KthPopularNamesReport.KthPopularNames("A",4,3,1234,2,1,"A"));
        testList.add(new KthPopularNamesReport.KthPopularNames("A","A"));
        KthPopularNamesReport testReport = new KthPopularNamesReport(testList,"",0);
        testReport.sortKthPopularNamesList();
        System.out.println(testReport.getKthPopularNamesList().equals(correctList));
        for (int i = 0; i < testList.size(); i++)
        {
            KthPopularNamesReport.KthPopularNames currentName2 = testList.get(i);
            KthPopularNamesReport.KthPopularNames currentName = testReport.getKthPopularNamesList().get(i);
            System.out.println(currentName.getName()+" "+currentName.getFrequency()+" "+currentName.getoccurrence()+" "+currentName.getPercentage()+" ");
            System.out.println(currentName2.getName()+" "+currentName2.getFrequency()+" "+currentName2.getoccurrence()+" "+currentName2.getPercentage()+" ");
        }

输出

false

A 5 1000 A 

A 5 1000 A 

A 4 1000 A 

A 4 1000 A 

A 3 1234 A 

A 3 1234 A 

A 2 1000 A 

A 2 1000 A 

A 1 1000 A 

A 1 1000 A 

解决方法

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