Laravel - 如何合并查询

问题描述

有两种模型 BoardArticle 和 BoardArticleLocation。

$articles = BoardArticle::where('board_id',$board_id)
    ->orderBy("id",'desc')
    ->paginate(20);

$boardlocation = BoardArticleLocation::select('location_top as top','location_top_text as text')
    ->addselect(DB::raw('CONCAT("[",group_concat(location_sub),"]") as sub'))
    ->where('board_article_id',$id)
    ->groupby('location_top')
    ->get();

所以，这些是我尝试过的方法。

$articles = BoardArticle::where('board_id',$searchKey,$board_id)
    ->select('board_articles.*')
    ->addselect(DB::raw('CONCAT("[",group_concat(DISTINCT location_top_text),"]") as location_text'))
    ->leftjoin('board_article_locations','board_articles.id','=','board_article_locations.board_article_id')
    ->groupby('board_articles.id')
    ->orderBy("id",'desc')
    ->paginate(20);

这个方法太慢了。

$articles = BoardArticle::where('board_id',$board_id)
    ->with('BoardArticleLocations')
    ->orderBy("id",'desc')
    ->paginate(20);

Models\BoardArticleLocation
public function BoardArticleLocations()
    {
        return $this->hasMany(BoardArticleLocation::class)
            ->select('location_top as top','location_top_text as text')
            ->addselect(DB::raw('CONCAT("[","]") as sub'))
            ->groupby('location_top');
    }

此方法没有查找任何项目。

我该怎么办？

解决方法

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eloquent laravel laravel laravel-models