如何使用 rusqlite 在 sqlite 数据库中插入和获取日期？

编程问答 2022-05-12

问题描述

我有一个带有 NaiveDate 字段的结构，我想将此字段插入到表中。这是我的全部代码

use chrono::naive::NaiveDate; 
use rusqlite::{params,Connection,Result};

#[derive(Debug)]
struct Person {
    id: i32,name: String,date: NaiveDate,}

fn main()->Result<()>{
    let date_str = "2020-04-12";
    let naive_date = NaiveDate::parse_from_str(date_str,"%Y-%m-%d").unwrap();

    let me = Person {
        id: 0,name: "Steven".to_string(),date: naive_date,};
    println!("{:?}",me);
    
    let conn = Connection::open_in_memory()?;
    
        
    conn.execute(
        "CREATE TABLE person (
                  id              INTEGER PRIMARY KEY,name            TEXT NOT NULL,date            TEXT
                  )",[],)?;
    
    conn.execute(
    "INSERT INTO person (name,date) VALUES (?1,?2)",params![me.name,me.date],)?;
    
    let mut stmt = conn.prepare("SELECT id,name,date FROM person")?;
    let person_iter = stmt.query_map([],|row| {
        Ok(Person {
            id: row.get(0)?,name: row.get(1)?,date: row.get(2)?,})
    })?;

    for person in person_iter {
        println!("Found person {:?}",person.unwrap());
    }
    
    Ok(())
}

但它给出了这两个错误

|   the trait `Fromsql` is not implemented for `NaiveDate`
|   the trait `Tosql` is not implemented for `NaiveDate`

cargo.toml

chrono = "0.4.19"
rusqlite = "0.25.0"

解决方法

您必须使用额外的 chrono 功能进行编译，才能为 chrono 类型实现 FromSql 和 ToSql 特征。

将 Cargo.toml 中的声明更改为

chrono = "0.4.19"
rusqlite = { version = "0.25.0",features = ["chrono"] }
rusqliterustrust-chrono