问题描述
我正在开发一个使用 python 模块“键盘”捕获键的键盘记录器。但是我的输出有问题。当我输入“Hello World”时,输出是flase。像这样:“shift-H-shift-e-e-l-l-o-space-W-o-r-l-d-d-enter
代码:
print("starting")
import keyboard # imports the keyboard-module
file = open("log.txt","w") # creates a file
nZ = 0
keyboard.unhook_all() # clears all keys that were typed in
def on_key(key):
file.write(str(key.name) + "\n") # writes the output to a file
file.flush() # saves the written stuff
while True:
keyboard.hook(on_key) # waits for a key typed in
keyboard.unhook_all() # again clears all keys that were typed in
nZ += 1
file.close()
所以它们有时是重复的,有时不是。这是为什么?是我的电脑变慢了,是模块本身还是我使用了错误的功能或类似的东西?
编辑 - 正确的代码:
print("starting")
import keyboard # imports the keyboard-module
file = open("log.txt","w") # creates a file
keyboard.unhook_all() # clears all keys that were typed in
def on_key(key):
file.write(str(key.name) + "\n") # writes the output to a file
file.flush() # saves the written stuff
while True:
keyboard.on_release(on_key) # waits for a key typed in
keyboard.unhook_all() # again clears all keys that were typed in
file.close()
import keyboard
rk = keyboard.record(until="Esc")
keyboard.play(rk)
解决方法
问题是钩子开火,松开,弹回并立即再次开火,因为仍然按下键。
您可以通过使用 // Get List_of_Packages where there is no match in List_sub_Activities after
// it is joined to Activities with the agency_id set.
const agencyId = 2;
const packages = await List_of_Packages.findAll({
attributes: ['list_name'],include: {
model: List_sub_Activities,// we don't need to actually fetch the list_id
attributes: [],include: {
model: Activities,where: {
agency_id: agencyId,},// uses a LEFT JOIN
required: false,// only return results where the List_sub_Activities.list_id is null
where: sequelize.where(sequelize.col('List_sub_Activities.list_id'),'IS',null),});
而不是 keyboard.on_release(on_key)
来防止这种情况发生。这会导致钩子只有在释放钥匙时才会触发。这样当钩子回弹时按键不再被按下。