问题描述
我已经将一些数据作为 JSON 字符串存储在表中,如下所示。
[
{
"firstName":"John","lastName":"Smith","age":25,"Address":{
"streetAddress":"21 2nd Street","city":"New York","state":"NY","postalCode":"10021"
},"PhoneNumbers":{
"home":"212 555-1234","fax":"646 555-4567"
}
},{
"firstName":"Mike","lastName":"Lee","age":30,"Address":{
"streetAddress":"10 Street","PhoneNumbers":{
"home":"212 555-3265","fax":""
}
}
]
要将这些数据导出到 excel 文件,我需要进行查询以获取如下详细信息
使用 CROSS APPLY OPEnjsON 我可以获得姓名和年龄,但如何将地址和联系方式作为列获取?
解决方法
您需要使用 OPENJSON()
和相应的 path
:
JSON:
DECLARE @json nvarchar(max) = N'[
{
"firstName":"John","lastName":"Smith","age":25,"Address":{
"streetAddress":"21 2nd Street","city":"New York","state":"NY","postalCode":"10021"
},"PhoneNumbers":{
"home":"212 555-1234","fax":"646 555-4567"
}
},{
"firstName":"Mike","lastName":"Lee","age":30,"Address":{
"streetAddress":"10 Street","PhoneNumbers":{
"home":"212 555-3265","fax":""
}
}
]'
声明:
SELECT *
FROM OPENJSON(@json) WITH (
FirstName nvarchar(100) '$.firstName',LastName nvarchar(100) '$.lastName',Age int '$.age',Name nvarchar(100) '$.firstName',StreetAddress nvarchar(100) '$.Address.streetAddress',City nvarchar(100) '$.Address.city',State nvarchar(100) '$.Address.state',PostalCode nvarchar(100) '$.Address.postalCode',HomePhone nvarchar(100) '$.PhoneNumbers.home',Fax nvarchar(100) '$.PhoneNumbers.fax'
)
结果:
FirstName LastName Age Name StreetAddress City State PostalCode HomePhone Fax
John Smith 25 John 21 2nd Street New York NY 10021 212 555-1234 646 555-4567
Mike Lee 30 Mike 10 Street New York NY 10021 212 555-3265