Javascript 将 WEBTT 文件转换为 json

问题描述

文件.vtt：

WEBVTT

00:00:00.039 --> 00:00:25.968
VINCENZO Cassano!

00:00:26.044 --> 00:00:26.961
Damn it.

00:01:23.434 --> 00:01:24.894
Mr. Vincenzo Cassano.

00:01:24.978 --> 00:01:27.814
You're under arrest
for the murder of Mr. Oh Jeong-bae.

00:01:43.913 --> 00:01:44.956
Hands up,00:01:45.540 --> 00:01:46.708
or I'll fire.

00:01:51.504 --> 00:01:52.964
I didn't do it.

转成json：

[
   {
      "from":"00:00:00.039","to":"00:00:25.968","timeString":"00:00:00.039 --> 00:00:25.968","text":"VINCENZO Cassano!"
   },....,{
      "from":"00:01:24.978","to":"00:01:27.814","timeString":"00:01:24.978 --> 00:01:27.814","text":"You're under arrest\nfor the murder of Mr. Oh Jeong-bae."<- Multi line,i assume it's a \n??
   }
]

结果：

我有一个 .vtt 文件，对于字幕，我必须确保创建一个如上所示的 json 数组，还要考虑多行。

我写了这个，它应该删除前导 WEBVTT 和双空格，但我无法删除前导空格，如下图所示，索引 0（也许这个问题是我解决的通过添加 .replace('\n',''))

来修复它

const v = enc.decode(text).replace('WEBVTT','').replace(/[\r\n]{2,}/g,'\n').replace('\n','');
const lines = v.split('\n');
lines.map((el,i) => console.log(`${i} - ${el}`));

const test = new RegExp('\\b(\\d{2}:\\d{2}:\\d{2})\\.(\\d{3})\\b').test(el);
<-- expression to check if the string is of the type 00:00:00.039

你能帮我一把吗？

解决方法

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