问题描述
class <YOUR_MODEL> extends Model
{
protected $fillable = [ 'column_name_1','column_name_2',..,'column_name_n' ];
}
我知道如何使用 For 循环:
punctuations="!@#$%^&*()_-=+:;{}[]<>,.?/\''"
analyzed=""
text="This is ;;;; $# @#%@$ A String <>?::"
但是我如何使用列表理解来做到这一点?
解决方法
punctuations="!@#$%^&*()_-=+:;{}[]<>,.?/\''"
analyzed=""
text="This is ;;;; $# @#%@$ A String <>?::"
试试这个:
>>[c for c in text if c not in punctuations]
您将获得:
['T','h','i','s',' ','A','S','t','r','n','g',' ']
如果您希望将其作为单个字符串,只需加入所有字符串即可。
>>''.join(c for c in text if c not in punctuations)
'This is A String '
,
使用生成器,并将其作为参数传递给 join()
以将结果转换回字符串。
analyzed = ''.join(c for c in text if c not in punctuations)
print(analyzed)
,
你可以先把你的标点符号和字符串转换成一个列表,然后分开,如下:
element
输出:
import string
list = ["!","This","@","#","$","is","%","a","^","&","list","*","(",")"]
list2 = [idx for idx in list if not any(punc in idx for punc in string.punctuation)]
print(str(list2))