C++ 程序，其中，从用户读取一个六位整数作为输入，并通过 for/While 循环

问题描述

/编写一个C++程序，从用户那里读取一个六位整数作为输入，并使用循环以words形式输出它的每个数字。/

#include <iostream>
using namespace std;
int main()
{
    int number,last_number,count = 0;
    cout << "Please enter a six digit number:" << endl;
    cin >> number;

    while (count < 6)
    {

         last_number = number % 10;


        if (last_number == 0)
            cout << "Zero ";
        else if (last_number == 1)
            cout << "One ";
        else if (last_number == 2)
            cout << "Two ";
        else if (last_number == 3)
            cout << "Three ";
        else if (last_number == 4)
            cout << "Four ";
        else if (last_number == 5)
            cout << "Five ";
        else if (last_number == 6)
            cout << "six ";
        else if (last_number == 7)
            cout << "Seven ";
        else if (last_number == 8)
            cout << "Eight ";
        else if (last_number == 9)
            cout << "Nine ";


        number = number / 10;
        count++;


    }
    cout << endl;
    return 0;

}

当我运行程序时，它输出相反的值，例如我想打印 123456 而不是输出一二三四五六它输出六五四三二一。我该如何解决这个问题？

解决方法

由于数字是从右到左分解的，所以显示的输出是相反的。 有几种方法可以解决这个问题，即您可以使用堆栈来推送输出值并以正确的顺序获取它们。例如，您还可以创建一个字符串，

string number = "";

number = last_number + " " + number;

,

好吧，您的逻辑中的问题是 last_number = number % 10; 因为当您除以数字时，您会得到最后一个元素，例如，如果将 12345 除以 10，您将得到 5 作为余数，这就是问题出现的地方尝试使用字符串和 for 循环会更容易

#include <iostream>
using namespace std;
int main()
{
    string  number;
    cout << "Please enter a six digit number" << endl;
    cin >> number;

    for (int i = 0; i < number.length(); i++) 
    {
        if (number[i] == '0')
            cout << "Zero ";
        else if (number[i] == '1')
            cout << "One ";
        else if (number[i] == '2')
            cout << "Two ";
        else if (number[i] == '3')
            cout << "Three ";
        else if (number[i] == '4')
            cout << "Four ";
        else if (number[i] == '5')
            cout << "Five ";
        else if (number[i] == '6')
            cout << "six ";
        else if (number[i] == '7')
            cout << "Seven ";
        else if (number[i] == '8')
            cout << "Eight ";
        else if (number[i] == '9')
            cout << "Nine ";

    }
    return 0;
}

,

last_number=number%10

这行代码给出了数字除以 10 的余数。所以 123%10 应该给你 last_number=3。

使用字符串的答案是正确的。但是，如果您想使用整数，这里有另一种使用递归的方法：

#include<iostream>
using namespace std;
void print_digit(int last_number){
    if (last_number == 0)
            cout << "Zero ";
        else if (last_number == 1)
            cout << "One ";
        else if (last_number == 2)
            cout << "Two ";
        else if (last_number == 3)
            cout << "Three ";
        else if (last_number == 4)
            cout << "Four ";
        else if (last_number == 5)
            cout << "Five ";
        else if (last_number == 6)
            cout << "six ";
        else if (last_number == 7)
            cout << "Seven ";
        else if (last_number == 8)
            cout << "Eight ";
        else if (last_number == 9)
            cout << "Nine ";
}
void get_digits(int number){
    if(number<10){
        print_digit(number);
        return;
    }
    get_digits(number/10);
    print_digit(number%10);
}
int main(){
    int number=12345;
    get_digits(number);
}

如果您不想使用递归，您可以使用您现在使用的相同逻辑并将 last_number 值存储在堆栈中。您可以找到更多方式here

,

您以相反的顺序得到结果，因为您是通过模数运算 (%) 从末尾提取每个数字。

要以正确的顺序得到答案，您可以先将原始数字反转，然后使用您正在使用的相同逻辑。

....
cin >> number;
int tmp_number = 0;  //temporary number to store reverse value of "number"
while ( number > 0 )
{
   tmp_number = tmp_number * 10 + number % 10;
   number = number / 10;
}

number = tmp_number;
while (count < 6)
....