问题描述
CurrentThermostatTemp
City
Cradley Heath 20.0
Cradley Heath 20.0
Cradley Heath 18.0
Cradley Heath 15.0
Cradley Heath 19.0
... ...
Walsall 16.0
Walsall 22.0
Walsall 20.0
Walsall 20.0
Walsall 20.0
[6249 rows x 1 columns]
唯一值是:
Index(['Cradley Heath','ROWLEY REGIS','Smethwick','Oldbury','West bromwich','Bradford','Bournemouth','Poole','Wareham','Wimborne',...
'St. Helens','Altrincham','runcorn','Widnes','St Helens','Wakefield','Castleford','Pontefract','Walsall','Wednesbury'],dtype='object',name='City',length=137)
我的目标是进行单向方差分析,即
from scipy.stats import f_oneway
用于数据框中的所有唯一值。这样做
SciPy.stats.f_oneway("all unique values")
并接收输出:所有变量的单向方差分析给出 {} 和 p 值 {} 这是我尝试过很多次但不起作用的方法:
all = Tempvs.index.unique()
Tempvs.sort_index(inplace=True)
for n in range(len(all)):
truncated = Tempvs.truncate(all[n],all[n])
print(f_oneway(truncated))
解决方法
IIUC 您需要一个方差分析测试,其中每个样本都包含唯一元素 Temp
的值 City
。如果是这种情况,您可以这样做
import numpy as np
import pandas as pd
import scipy.stats as sps
# I create a sample dataset
index = ['Cradley Heath','ROWLEY REGIS','Smethwick','Oldbury','West Bromwich','Bradford','Bournemouth','Poole','Wareham','Wimborne','St. Helens','Altrincham','Runcorn','Widnes','St Helens','Wakefield','Castleford','Pontefract','Walsall','Wednesbury']
np.random.seed(1)
df = pd.DataFrame({
'City': np.random.choice(index,500),'Temp': np.random.uniform(15,25,500)
})
# populate a list with all
# values of unique Cities
values = []
for city in df.City.unique():
_df = df[df.City==city]
values.append(_df.Temp.values)
# compute the ANOVA
# with starred *list
# as arguments
sps.f_oneway(*values)
在这种情况下,将给
F_onewayResult(statistic=0.4513685152123563,pvalue=0.9788508507035195)
PS:不要使用all
作为变量,因为它是python内置函数,见https://docs.python.org/3/library/functions.html#all