在 Java 中从浮点变量的输出中删除小数

问题描述

我想使用严格的浮点变量根据虚构的货币对纸币和硬币进行排序。我的代码快完成了，我只需要从输出中删除小数即可。 输出可以是 n.00 格式，或者理想情况下是 n 格式。 欢迎提出所有建议。

示例代码：

package TEST;
import java.util.Scanner;
import java.lang.Math;
public class TEST {
  public static void main(String[] args) {
  Scanner scanner = new Scanner(System.in);
  //let a be currency value,r the reminder,and n the number of banknotes and coins
  float a = scanner.nextFloat();
  float r = a%500; float n = a/500;
  //500,100,50,20,10,5,2 banknotes; and 0.50,0.25,0.10,0.05 and 0.01 coins.
  
  System.out.printf("Value of currency: %5.2f%n",a);
  System.out.printf("Number of 500 banknotes: %5.2f%n",n);
  
  if (r != 0) {
      a=r; r=a%100; n=a/100; System.out.printf("Number of 100 banknotes: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%50; n=a/50; System.out.printf("Number of 50 banknotes: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%20; n=a/20; System.out.printf("Number of 20 banknotes: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%10; n=a/10; System.out.printf("Number of 10 banknotes: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%5; n=a/5; System.out.printf("Number of 5 banknotes: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%2; n=a/2; System.out.printf("Number of 2 banknotes: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%0.50f; n=a/0.50f; System.out.printf("Number of 0.50 coins: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%0.25f; n=a/0.25f; System.out.printf("Number of 0.25 coins: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%0.10f; n=a/0.10f; System.out.printf("Number of 0.10 coins: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%0.05f; n=a/0.05f; System.out.printf("Number of 0.05 coins: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%0.02f; n=a/0.02f; System.out.printf("Number of 0.02 coins: %5.2f%n",n);
  if (r != 0) {
      a=r; r=a%0.01f; n=a/0.01f; System.out.printf("Number of 0.01 coins: %5.2f%n",n);
  }}}}}}}}}}}}
  }}

示例输出：

666.666
Value of currency: 666.67
Number of 500 banknotes:  1.33
Number of 100 banknotes:  1.67
Number of 50 banknotes:  1.33
Number of 20 banknotes:  0.83
Number of 10 banknotes:  1.67
Number of 5 banknotes:  1.33
Number of 2 banknotes:  0.83
Number of 0.50 coins:  3.33
Number of 0.25 coins:  0.66
Number of 0.10 coins:  1.66
Number of 0.05 coins:  1.32
Number of 0.02 coins:  0.80
Number of 0.01 coins:  1.60

理想输出：

666.666
Value of currency: 666.67
Number of 500 banknotes:  1
Number of 100 banknotes:  1
Number of 50 banknotes:  1
Number of 20 banknotes:  0
Number of 10 banknotes:  1
Number of 5 banknotes:  1
Number of 2 banknotes:  0
Number of 0.50 coins:  3
Number of 0.25 coins:  0
Number of 0.10 coins:  1
Number of 0.05 coins:  1
Number of 0.02 coins:  0
Number of 0.01 coins:  1

解决方法

将浮点数转换为整数。

float f = 2.65f;
int i = (int)f;
System.out.println(i);

// or
System.out.printf("%d%n",(int)f);
        

印刷品

2
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