python脚本使用vlc从RaspberryPi播放音频

问题描述

我很想每天在同一时间获取在我的 RaspBerryPi 上运行的歌曲列表。为此，我编写了一个 Python 脚本并计划将其作为 cronjob 运行。

我写的脚本如下。

import vlc
import glob
import time

base_folder = '/home/pi/Music/'


def play_song(song):
    player = vlc.MediaPlayer(song)
    player.play()

    
def add_media(player,media_list,playlist):
    for song in playlist:
        print('sing " {0}'.format(song))
        media = player.media_new(song)    
        media_list.add_media(media)
        
    media_player.set_media_list(media_list)

  
playlist = glob.glob(base_folder + "/" + "*.mp3")
media_player = vlc.MediaListPlayer()
player = vlc.Instance()    
media_list = vlc.MediaList()
add_media(player,playlist)

我对上述程序有一个问题。

当我从 Thonny 运行 python 程序时，它是 RaspBerryPi 的默认 python IDE，它可以工作。 （即它播放歌曲）。但是，当我从命令行运行它时

python3 audioplayer.py

它不播放歌曲就退出。如何让它在从命令行运行时播放歌曲。

解决方法

您发布的脚本中似乎缺少一些代码，即 play 命令。

我怀疑 IDE 正在为 vlc 打开主循环，因此它可以工作。
但是，从命令行来看，没有循环，这就是您所缺少的。

尝试以下操作：

import vlc
import glob
import time

base_folder = '/home/rolf'
# vlc State 0: Nowt,1 Opening,2 Buffering,3 Playing,4 Paused,5 Stopped,6 Ended,7 Error
playing = set([1,2,3,4])

def add_media(inst,media_list,playlist):
    for song in playlist:
        print('Loading: - {0}'.format(song))
        media = inst.media_new(song)    
        media_list.add_media(media)
        
playlist = glob.glob(base_folder + "/" + "*.mp3")
playlist = sorted(playlist)
#playlist = ['./2005.mp3','./vp1.mp3']
media_player = vlc.MediaListPlayer()
inst = vlc.Instance('--no-xlib --quiet ') 
media_list = vlc.MediaList()
add_media(inst,playlist)

media_player.set_media_list(media_list)
media_player.play()
time.sleep(0.1)
current = ""
idx = 1
player = media_player.get_media_player()
while True:
    state = player.get_state()
    if state.value not in playing:
        break
    title = player.get_media().get_mrl()
    if title != current:
        print("\nPlaying - {0}\t{1} of {2}".format(str(title),idx,len(playlist)))
        current = title
        idx += 1
    time.sleep(1.0)
print("\nPlaylist Finished")