问题描述
给出这个简化的例子，表达函数 import numpy as np
from flask import Flask
from flask import request,jsonify,render_template
import pickle
app = Flask(name)
model = pickle.load(open('diagnosis_model2.pkl','rb'))
@app.route('/')
def home():
return '<h1> API server is working </h1>'
@app.route('/predict')
def predict():
diagnosis_predict= model.predict([[request.args['Symptom_1'],request.args['Symptom_2'],request.args['Symptom_3'],request.args['Symptom_4'],request.args['Symptom_5'],request.args['Symptom_6'],request.args['Symptom_7'],request.args['Symptom_8'],request.args['Symptom_9'],request.args['Symptom_10'],request.args['Symptom_11']]])
return str(diagnosis_predict)
if name == 'main':
app.run(debug=True)
可以接受任何动物但只让吠叫的动物吠叫的正确方法是什么。
makeAnimalBark我明白为什么我会看到错误，但我不确定处理这种情况的正确方法。
解决方法
// Without `A` extending from something that has a `bark`
// property,TS complains that `bark` doesn't exist on `A`.
那是因为您输入的 bark 是可选的
interface PotentiallyBarkingAnimal {
// remove the ? to make bark mandatory
bark?: () => void
}
// Here,TS complains that `Cat` has no properties
// in common with `PotentiallyBarkingAnimal`.
那是真的，对吧？如果您查看它的 Cat 界面，它没有与 bark 共享的属性 (PotentiallyBarkingAnimal)。您需要让PotentiallyBarkingAnimal知道meow。